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Vilka [71]
3 years ago
9

Describe something true about any pair of interior and exterior angles?​

Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0
The interior angles of a shape are the angles inside the shape. The exterior angles are the angles formed between a side-length and an extension. Rule: Interior and exterior angles add up to 180 ° 180\degree 180°.
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Please help with math
Olenka [21]

Answer:

648 cm³

Step-by-step explanation:

side area=(13+11)/2 ×9=12×9=108 cm²

volume=108×6=648 cm³

6 0
3 years ago
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Akimi4 [234]

Answer:

The answer is 5!!

7 0
3 years ago
C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature
Alona [7]

Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

5 0
3 years ago
Brainiest to whoever right
Anna35 [415]

Answer:

since M lies between point A and B , we came to know that,

M(4,6) =(x,y)

A(-2,-1)=(x1 ,y1)

B( _, _ )=(x2,y2)

Now using mid point formula,

x=x1×x2÷2 y=y1+y2÷2

so, point B is (10,13)

6 0
3 years ago
Reduce 7y + 2y 2 - 7 by 3 - 4y.
NARA [144]

Answer:

D. 2y^2+11y-10.

Step-by-step explanation:

Given:

We need to reduce 7y+2y^2-7 by 3-4y

Solution:

To reduce the equation means we need to subtract the one equation from other.

First we will arrange the equation n proper format we get;

2y^2+7y-7  ⇒ equation 1

Also Arranging other equation we get;

-4y+3   ⇒ equation 2

Now we will subtract equation 2 from equation 1 we get;

(2y^2+7y-7)-(-4y+3)

Now Applying distributive property for the sign we get;

2y^2+7y-7+4y-3

Now Arranging the like terms we get;

2y2+7y-+4y-7-3\\\\2y^2+11y-10

Hence the reduce form of the given equation is 2y^2+11y-10.

7 0
3 years ago
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