Answer:
(arranged from top to bottom)
System #3, where x=6
System #1, where x=4
System #7, where x=3
System #5, where x=2
System #2, where x=1
Step-by-step explanation:
System #1: x=4

To solve, start by isolating your first equation for y.

Now, plug this value of y into your second equation.

System #2: x=1

Isolate your second equation for y.

Plug this value of y into your first equation.

System #3: x=6

Isolate your first equation for y.

Plug this value of y into your second equation.

System #4: all real numbers (not included in your diagram)

Plug your value of y into your second equation.

<em>all real numbers are solutions</em>
System #5: x=2

Isolate your second equation for y.

Plug in your value of y to your first equation.

System #6: no solution (not included in your diagram)

Isolate your first equation for y.

Plug your value of y into your second equation.

<em>no solution</em>
System #7: x=3

Plug your value of y into your second equation.

When you have the same denominator. Other than that have different denominators will not be possible.
Step 1
Let n represent car and m represent motorcycles.
n + m = 50 ...................1
car has four wheels and motorcycle has two wheels
4n + 2m = 164 .............................. 2
Step 2
Solve equation 1 and 2 simultaneously.
from (1), make n subject of relation and substitute in equation 2.
n = 50 - m
Step 3
Substitute n in equation 2
4(50 - m) + 2m = 164
200 - 4m + 2m = 164
collect like terms
200 - 164 = 4m - 2m
36 = 2m
m = 36/2
m = 18
next find n
n = 50 - m
n = 50 - 18
n = 32
There are 32 cars and 18 motorcycles.
Answer:
32 + x= 90
x= 90- 32 = 58
x + y = 90
38 + y= 90
y= 90-38
y = 52
Step-by-step explanation:
|2(-5) - 1| + 10
|-10-1| + 10
|-11| + 10
11 + 10
21 is your answer
Hope this helped!