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In-s [12.5K]
4 years ago
12

This is a project that’s due this Friday. I need help on everything pleaseeee help me.

Mathematics
1 answer:
pishuonlain [190]4 years ago
8 0

Answer:

ok fking fk it ill just tell you, the most affordable way is doing it as a 4*3 package, the length will be 16, width 12, and the height 5. the area will be 960in^3, and the SA will be 664 in^2

Step-by-step explanation:

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Did Meg make it home on time if she spent 22 minutes at the library. 38 minutes at her grandmas house. She walked for 17 minutes
Tomtit [17]
Not enough info to answer
4 0
3 years ago
Find the solutions to 2x^2-7x+3=0
GarryVolchara [31]

Answer:

X=½ or 3

Step-by-step explanation:

0=2x²-7x+3

0=(2x-1)(x-3)

0=2x-1 or 0=x-3

1=2x or 3=x

½=x

4 0
3 years ago
Janie has $3. She earns $1.20 for each chore she does and can do fractions of chores. She wants to earn enough money to buy a CD
d1i1m1o1n [39]

Answer:

The fraction of chores which Janie wants to earn enough money to buy a CD for $13.50 are 8.75~9 chores

Step-by-step explanation:

Given that Janie has $3. She earns $1.20 for each chore she does and can do fractions of chores. She wants to earn enough money to buy a CD for $13.50.

we have to find the fraction of chores Janie did to earn total of $13.50

Let the fraction of chores is x which Janie wants to earn enough money to buy a CD for $13.50.

Total money=$3+$1.20(fraction of chores)

$13.50=$3+$1.20(x)

$13.50-$3=$1.20(x)

x=8.75~9

Hence, the fraction of chores which Janie wants to earn enough money to buy a CD for $13.50 are 8.75~9 chores

6 0
3 years ago
Read 2 more answers
7. The prime factorization of which number is 2^5 x 5?<br> A) 50<br> B) 125<br> C) 160<br> D) 500​
QveST [7]
C is the right answer!!!
3 0
3 years ago
Find the distance from point (-1, 3) to the line 5 x - 4 y = 10.
Wewaii [24]

We could use the formula, derive the formula, or just work it out for this case.  Let's do the latter.

The distance of a point to a line is the length of the perpendicular from the line to the point.

So we need the perpendicular to 5x-4y=10 through (-1,3).  To get the perpendicular family we swap x and y coefficients, negating one.  We get the constant straightforwardly from the point we're going through:

4x + 5y = 4(-1)+5(3) = 11

Those lines meet at the foot of the perpendicular, which is what we're after.

4x + 5y = 11

5 x - 4y = 10

We eliminate y by multiplying the first by four, the second by five and adding.

16x + 20y  = 44

25x - 20y = 50

41x = 94

x = 94/41

y  = (11 - 4x)/5 = 15/41

We want the distance from (-1,3) to (94/41,15/41)

d = \sqrt{ (-1 - 94/41)^2 + (3 - 15/41)^2 } = \dfrac{27}{\sqrt{41}}

8 0
4 years ago
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