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Readme [11.4K]
3 years ago
13

On December 31, 2008, Ed Abbey Co. performed environmental consulting services for Hayduke Co. Hayduke was short of cash, and Ab

bey Co. agreed to accept a $200,000 zero-interest-bearing note due December 31, 2010, as payment in full. Hayduke is somewhat of a credit risk and typically borrows funds at a rate of 10%. Abbey is much more creditworthy and has various lines of credit at 6%.
Instructions
(a) Prepare the journal entry to record the transaction of December 31, 2008, for the Ed Abbey Co.
(b) Assuming Ed Abbey Co.’s fiscal year-end is December 31, prepare the journal entry for December 31, 2009.
(c) Assuming Ed Abbey Co.’s fiscal year-end is December 31, prepare the journal entry for December 31, 2010.
(d) Assume that Ed Abbey Co. elects the fair value option for this note. Prepare the journal entry at December 31, 2009, if the fair value of the note is $185,000.
Business
1 answer:
Veronika [31]3 years ago
5 0
Hmmmmmmmmmmmmmmmmmm, I’m confused l
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Read 2 more answers
An investment has an expected return of 11 percent per year with a standard deviation of 26 percent. Assuming that the returns o
Keith_Richards [23]

Answer:

P(X

And we can find this probability using the normal standard distribution table or excel and we got:

P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the expected return, and for this case we know the distribution for X is given by:

X \sim N(11,26)  

Where \mu=11 and \sigma=26

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard distribution table or excel and we got:

P(Z

4 0
3 years ago
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