Hello there!
The lines 2y - x = 6 and 6x - 3y - 33 = 0 are Neither <span>parallel nor perpendicular.
They are intersecting lines. So, the answer is Neither.
I hope this helps!</span>
Perimeter = 2L + 2W = 256
"8 feet longer than it is wide"
translates to
L = 8 + W
we plug that into the first equation and get
2(8 + W) + 2W = 256
now we solve for W
distribute the 2
16 + 2W + 2W = 256
add like terms
16 + 4W = 256
subtract 16 from both sides
4W = 240
divide both sides by 4
W = 60
plug that into
L = 8 + W
and solve for L now
L = 8 + 60
so
L = 68
therefore your
length = 68
and
width = 60
Answer: Y=20
Step-by-step explanation:
X is doubled from 3 to 6 meaning that y is also doubled.
Double 10 is 20 so y=20.
Answer:
Step-by-step explanation:
When a quadrilateral is inscribed in a circle, the opposite angles of it add up to 180 degrees.
Here,
∠DCB + ∠DAB = 180 (Opposite angles of a quad inscribed in a circle.)
<u>Given that:</u> ∠DCB = 135° and ∠DAB = x
135 + x = 180
Subtract 135 to both sides
x = 180 - 135
x = 55°
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
Step-by-step explanation:
discriminant=b²-4ac=8²-4(7)(2)=64-56=8
