All categories

3 years ago

Given this regular hexagon, what is the measurement of angle NOF?

Mathematics

2 answers:

Dimas [21]3 years ago

6 0

The angle NOF would be 45°

ASHA 777 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

N is 90 degrees. 180-90 = 90. 90/2 = 45 degrees

You might be interested in

True or false two lines with the same y intercept are perpendicular

tensa zangetsu [6.8K]

It is true your welcome.

4 0

4 years ago

Help with simple interest rate P=$18,000, r= 7.5%, t=18 months

n200080 [17]

=2025
change 18months to years=1.5 years then you use the formula
PRT÷100
$18000 \times 7.5 \times 1.5 = 202500 \div 100 = 2025$

7 0

4 years ago

Whats 1+1? I forgotttyt

vfiekz [6]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A group of 31 friends gets together to pay a sport. First, people must be divided into teams. Each team has to have exactly 3 pl

Monica [59]

Answer:

10 teams (1 remainder)

Step-by-step explanation:

if each team has 3 players and there are 30 friends, divide that and youll end up with 10 teams. you will also have 1 remaining player

5 0

2 years ago

Find the simplified product b-5/2b x b^2+3b/b-5

White raven [17]

Answer:

The product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

Step-by-step explanation:

Given expression $\frac{b-5}{2b}$ and $\frac{b^2+3b}{b-5}$

We have to find the product of $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Consider the given expression $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Multiply fractions, we have,

$\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}$

$=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}$

Cancel common factor ( b - 5 )

we have, $=\frac{b^2+3b}{2b}$

Apply exponent rule,

$\:a^{b+c}=a^ba^c$

$b^2=bb$

$=bb+3b=b(b+3)$

$=\frac{b\left(b+3\right)}{2b}$

Cancel common factor b , we have,

$=\frac{b+3}{2}$

Thus, the product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

8 0

4 years ago

Read 2 more answers