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2 years ago

Anybodyyy know how to do thisss ???

Mathematics

1 answer:

Kamila [148]2 years ago

8 0

Answer:

volume of a sphere is ⁴/³π r³

⁴/³ ×3.14 × 23³

3 goes into 3.14 , 1.047 times

4 ×1.047×23³

50939.17

Step-by-step explanation:

hope itade sense

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The angles shown are supplementary. What is the value of x?

Nookie1986 [14]

Answer:

X= 17

Step-by-step explanation:

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2 years ago

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The phenomenon of bottle flipping has hit the nation. You design a machine that can randomly flip a bottle. You observe 2180 ran

krek1111 [17]

Answer:

The variable of interest is the proportion of flips that land the correct way when flipped randomly.

The necessary conditions $n\pi \geq 10$ and $n(1-\pi) \geq 10$ are present.

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

Step-by-step explanation:

Variable of Interest:

Proportion of flips that land the correct way when flipped randomly.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Necessary conditions:

The necessary conditions are:

$n\pi \geq 10$

$n(1-\pi) \geq 10$

You observe 2180 random, independent flips, and 325 land the correct way.

This means that $n = 2180, \pi = \frac{325}{2180} = 0.149$

Necessary conditions

$n\pi = 2180*0.149 = 325 \geq 10$

$n(1-\pi) = 2180*0.851 = 1855 \geq 10$

The necessary conditions $n\pi \geq 10$ and $n(1-\pi) \geq 10$ are present.

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.33$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 - 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.131$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 + 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.167$

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

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2 years ago

What is 103.468 rounded to nearest liter

vlada-n [284]

103.468L rounded to the nearest liter would be 103L

3 0

2 years ago

1 Easy math please help

Oksi-84 [34.3K]

(-4/5)X=80

X=80*(-5/4)

X=-100

6 0

2 years ago

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Please help due soon!!!

il63 [147K]

Answer: 1,-1,-7

Step-by-step explanation:

-3-2(-2)= -3+4= 1

-3-2(-1)= -3+2= -1

-3-2(2)= -3-4= -7

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2 years ago