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Bingel [31]
3 years ago
9

What is 3x?

Mathematics
1 answer:
MissTica3 years ago
6 0

Answer: 3 · 30= 90

Step-by-step explanation:

yes you are correct

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If a triangle has a base of 64 m and a height of 7.3 m then what is the area of the triangle? please show your work!
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Use the distributive property to find (y+6)(y+4)​
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Answer:

Look down below for the answer :))

Step-by-step explanation:

y + 6 = 6y

y + 4 = 4y

4y x 6y = 24y

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Solve pls, ans should be 0, add working
Bond [772]

Step-by-step explanation:

<u>Given</u>: {x+(1/x)}³ = 3

<u>Asked</u>: x³ + (1/x³) = ?

<u>Solution:</u>

<u>Method</u><u> </u><u>1:</u>

We have, {x+(1/x)}³ = 3

Comparing the expression with (a+b)³, we get

a = x

b = (1/x)

Using identity (a+b)³ = a³+b³+3ab(a+b), we get

⇛{x+(1/x)}³ = 3

⇛(x)³ + (1/x)³ + 3(x)(1/x){x + (1/x)} = 3

⇛(x*x*x) + (1*1*1/3*3*3) + 3(x)(1/x){x + (1/x)} = 3

⇛x³ + (1/x³) + 3(x)(1/x){x + (1/x)} = 3

⇛x³ + (1/x³) + 3{x + (1/x)} = 3

⇛x³ + (1/x³) + 3(x) + 3(1/x) = 3

⇛x³ + (1/x³) + 3x + (3/x) = 3

Our answer came incorrect.

Let's try..

<u>Method</u><u> </u><u>2</u><u>:</u>

We have,

[x+(1/x)]³ = 3

On taking cube root both sides then

⇛³√[{ x+(1/x)}³ ] = ³√3

⇛x+(1/x) = ³√3 -----(1)

We know that

a³+b³ = (a+b)³-3ab(a+b)

⇛x³+(1/x)³ = [x+(1/x)]³ - 3(x)(1/x)[x+(1/x)]

⇛x³+(1/x³) = (3)-3(1)(³√3)

[since, {x + (1/x)} = ³√3 from equation (1)]

⇛x³+(1/x)³ = 3-3 ׳√3

⇛x³ + (1/x³) = 3- ³√81 (or )

⇛x³ + (1/x³) = 3(1-³√3)

Therefore, x³ + (1/x³) = 3(1 - cube root of 3)

It is impossible to get zero

6 0
2 years ago
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