All categories

2 years ago

Sin 40 cos 50 + cos 40 sin 50 find the value

Mathematics

1 answer:

skad [1K]2 years ago

4 0

Answer:

= 1

Step-by-step explanation:

0.4131 + 0.5868 = 0.999 --> 1

You might be interested in

Help me with these problems please

Scorpion4ik [409]

1. y = 7
2. 0
3. m = -1
4. k = -4
5. x = -6
6. There is no solution for these equations.

Please let me know if you want explanations/work shown!! Hope this helps :)

7 0

3 years ago

Will give brainliest

nalin [4]

Answer:

give me brainliest first

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Can u guys help wit a little bit more questions what is 9.04-6.98

Goryan [66]

Answer:

9.04-6.98=2.06

4 0

2 years ago

What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?

Akimi4 [234]

$\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------$

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5$

4 0

2 years ago

Read 2 more answers

Find the measurements

alexandr1967 [171]

Answer:

X=75 y=90

Step-by-step explanation:

180-105=75

X=75

180-90=90

Y=90

5 0

2 years ago

Sin 40 cos 50 + cos 40 sin 50 find the value​

Sin 40 cos 50 + cos 40 sin 50 find the value