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3 years ago

What is the square root of -1?

Mathematics

1 answer:

erik [133]3 years ago

6 0

Answer: i

Step-by-step explanation:

It is imaginary, since if you try squaring numbers, ex: -1, 1,0,2 you always get a number bigger or equal to 0.

For years mathematicans argued weather the square root of -1 (or any negative number) should exist.

Then one day, a mathematician proposed a soulution, the square root of -1 could be i. Everyone liked that and so now the square root of -1 is i

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Is the equations of quadratic number pattern will always have real roots

algol [13]

No, not at all.

The general quadratic equation is

Ax² + Bx + C = 0 .

The roots are real only if (B² - 4AC) is not negative.

That means if you graph it, it touches or crosses the x-axis.

If the graph is up in the air and never touches the x-axis,
then it has no real roots.

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3 years ago

In science class, the girl to boy ratio is 3 to 7. If there are 50 students total in class, how many are boys

Rzqust [24]

Step-by-step explanation:

3 girls:7 boys

50 students total

You have to multiply 7 by 5 to get 35

If you already multiplied one side by five, then you have to multiply the other side by five

3 times 5 is 15

15 + 35 = 50

So the

Answer is

35 boys

3 0

3 years ago

PLEASE HELP IM BEGGING YOU. PLEASE DONT ANSWER IF YOU DONT KNOW.

kirill [66]

Answer:

5.460

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

-3|9x-7|=2 Find the answer for x

labwork [276]

<h2>Solving Equations with Absolute Expressions</h2><h3>Answer:</h3>

No Solutions

<h3>Step-by-step explanation:</h3>

Given:

$-3|9x -7| = 2$

Rewriting the given equation:

$-3|9x -7| = 2 \\ |9x -7| = -\frac{2}{3}$

We have to realize that the right side of the equation, $|9x -7|$ , will always be positive no matter what real values of $x$ (because we're taking the absolute value of the expression) and we are equating it to a negative constant number, $-\frac{2}{3}\\$ . Something that is always positive will never be negative so there's no value for $x$ that satisfies the solution.

$\rule{6.5cm}{0.5pt}$

You may not read the following passage that I have written.

$\rule{6.5cm}{0.5pt}$

Solving by positive of the expression:

$9x -7 = -\frac{2}{3} \\ 9x = -\frac{2}{3} +7 \\ 9x = -\frac{2}{3} +\frac{21}{3} \\ 9x = \frac{19}{3} \\ 9x \times \frac{1}{9} = \frac{19}{3} \times \frac{1}{9} \\ x = \frac{19}{27}$

Solving by the negative of the expression:

$-(9x -7)= -\frac{2}{3} \\ 9x -7 = \frac{2}{3} \\ 9x = \frac{2}{3} +7 \\ 9x = \frac{2}{3} +\frac{21}{3} \\ 9x = \frac{23}{3} \\ 9x \times \frac{1}{9} = \frac{23}{3} \times \frac{1}{9} \\ x = \frac{23}{27}$

Checking: $x = \frac{19}{27}\\$

$-3|9(\frac{19}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|-\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{19}{27}\\$ is an extraneous solution.

Checking: $x = \frac{23}{27}\\$

$-3|9(\frac{23}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{23}{27}\\$ is an extraneous solution.

8 0

3 years ago

The staff at the community center make a rectangular skating pit every year. They use 100 meters of boarding to enclose it. So t

Sliva [168]

For a width of 25, the length will also be 25, so the area is 25² = ...
625.

_____
The rule is
area = width×(50 -width)

3 0

3 years ago