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salantis [7]
2 years ago
7

IF A CUBE IS 1CM ON A SIDE, CALCULATE ITS SURFACE AREA. HINT WRITE 2 points

Biology
1 answer:
frosja888 [35]2 years ago
7 0

Answer:

Surface area of the cube = 6cm²

Volume of the cube = 1cm³

Explanation:

The surface area of a cube, which refers to the sum of all the areas of the faces of the cube can be calculated using the formula:

S.A = 6 × a²

That is; a² + a² + a² + a² + a² + a²

Where;

a = length of a side of a cube

a² = area of one side of a cube

Note that, a cube has 6 faces

According to this question, a cube has a length of 1cm on each side.

Hence, S.A = 6 × 1²

S.A = 6 × 1

S.A = 6cm²

Volume of the cube can be calculated using the formula: a³

Where a = 1

Volume = 1 × 1 × 1

Volume = 1cm³

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3 years ago
Read 2 more answers
A geneticist is studying two genes. each gene can be either dominant or recessive. a sample of 100 individuals is categorized as
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Attached is a table. I found the exercise on another page on the internet and the sample of 100 individuals was categorised on a table - easier to understand than as it is presented here.
<span>"(a) what is the probability that a random sampled individual, gene 1 is dominant" - We should first add up all of the individuals that are dominant for gene 1 (56+24) and then divide it by the total number of individuals (100).
</span>\frac{56+24}{100}  =0.8
<span>The probability is of 8 in 10 individuals.
"</span><span>(b) what is the probability that a random sampled individual, gene 2 is dominant" - Follow the same logic as in the previous question.
</span>\frac{56+14}{100} =0.7
<span>The probability is of 7 in 10 individuals.
</span>"<span>(c) given that gene 1 is dominant, what is the probability that gene 2 is dominant" - Because we are considering those that are dominant for gene 1, our total number of individuals is the total individuals that are dominant for gene 1 and not the whole 100. Once we have this restriction, and we want to know the probability that gene 2 is dominant in these individuals, we should also only consider those that are dominant for gene 2.
</span>\frac{56}{56+24} =0.7
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