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sashaice [31]
3 years ago
6

The student council made a pront of $3,000 on a car wash. If they invest the money at 5% interest

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer:

$3375 money would the student council have in four years if they invest $3000 at 5% interest compounded yearly.

Step-by-step explanation:

We are given:

Principal Amount = $3000

Interest Rate r = 5% or 0.05

n=1 (compounded yearly)

Years t= 4

We need to find future value (A)

The formula used is: A=P(1+\frac{r}{n})^{nt}

Putting values in formula and finding future value A

A=P(1+\frac{r}{n})^{nt}\\A=3000(1+\frac{0.05}{1})^{1*4}\\A=3000(1+0.05)^4\\A=3000(1.05)^4\\A=3000(1.215)\\A=3375

So, $3375 money would the student council have in four years if they invest $3000 at 5% interest compounded yearly.

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Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)
sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ABC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|

On solving we get:

Area\,of\,triangle\,=25.

In Δ ADC:

A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ADC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|

On solving it by same process as above we get:

Area\,of\,triangle\,=114

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

25+114\\=25+114\\=139\ unit^2

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0
3 years ago
Please help
madam [21]

Answer:

Step-by-step explanation:

1 × a = a

a² = a*a ; a³ = a*a*a .....

(\frac{a}{b}) ^{n} = \frac{a^{n} }{b^{n}  }

<em>(1).</em>

(a). 7^{5}

(b). (\frac{1}{7}) ^{6} = \frac{1}{7^{6} }

(c). (9.3)^{9}

<em>(2).</em>

(e). (\frac{1}{2} )^{4} =\frac{1}{2^{4} } = \frac{1}{2*2*2*2} = \frac{1}{16}

(f). (\frac{1}{3} )^{2} = \frac{1}{3} × \frac{1}{3} = \frac{1}{9}

<em>(3).</em>

x² = 30² + 16² = 900 + 256 = 1156 = 34² ⇒ <em>x = 34 units</em>

3 0
3 years ago
Can someone pls explain what I’m supposed to do I don’t really understand
kirill [66]

Answer:

There are only 3 differences perform

Step-by-step explanation:

I. If x is negative, y is negative then the answer is possitive

            eg. x is -2, y is -3

                  -2 × -3 = 6

II. If x is negative, y is positive then the answer is negative

            eg. x is -1, y is 2

                  -1 × 2 = -2

III. If x is possitive, y is possitive then the answer is positive

             eg. x is 2, y is 5

                    2 × 5 = 10

Alt. No matter how long x, y, z, a, b there always apply only 3 rules above. Multiply or Devide are the same rule.

Ask me for anything :D

8 0
3 years ago
NEED HELP on this one ASAP
Rudiy27

Answer:

<h2><u><em>A) 0.88 for 4 oz</em></u></h2>

6 0
4 years ago
6p+4+2p combine terms
tino4ka555 [31]

Answer:

8p + 4

Step-by-step explanation:

6p + 4 + 2p

(6p + 2p) + 4

8p + 4

Best of Luck!

7 0
4 years ago
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