Which of the following inequalities matches the graph?

Mathematics

1 answer:

Alik [6]3 years ago

8 0

A vertical line has an equation of the form x = k, where k is the x-coordinate of all points on the line.
You have a vertical line. It passes through the point (-3, 0), so for this line, k = -3.
The vertical line has equation x = -3.
The line is dashed, not solid, so you have either < or >, but not <= or >=.
Also, notice the shading is to the left of x = -3, so all values of x are less than -3.
The inequality is

x < -3

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If 6^4x = 82, what is the value of x?<br> Round your answer to three places.

neonofarm [45]

Answer:

$x=0.61485921$

Step-by-step explanation:

The given equation is in exponential form:

$6^{4x} =82$

To find $x$ we need to write it in logarithmic form:

$b^{a} =n$ ⇒ $log_{b} n=a$

$6^{4x} =82$ ⇒ $log_{ 6 } 82=4x$

$2.45943684 = 4x$

$\frac{2.45943684}{4} = x$

$0.61485921 =x$

To prove this, we can substitute the value into the given equation

$6^{4x} =82$

$6^{4(0.61485921)} =82$

$82=82$

Therefore, the answer is $x=0.61485921$

6 0

3 years ago

x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y −

snow_tiger [21]

For this case, what we must do is fill squares in all the expressions until we find the correct result.
We have then:

x2 + y2 − 4x + 12y − 20 = 0 x2 + y2 − 4x + 12y = 20
x2 − 4x + y2 + 12y = 20
x2 − 4x + (12/2)^2 + y2 + 12y + (-4/2)^2 = 20 + (12/2)^2 + (-4/2)^2
x2 − 4x + (6)^2 + y2 + 12y + (-2)^2 = 20 + (6)^2 + (-2)^2
x2 − 4x + 36 + y2 + 12y + 4 = 20 + 36 + 4
(x − 2)2 + (y + 6)2 = 60

3x2 + 3y2 + 12x + 18y − 15 = 0
x2 + y2 + 4x + 6y − 5 = 0
x2 + y2 + 4x + 6y = 5
x2 + 4x + (4/2)^2 + y2 + 6y + (6/2)^2 = 5 + (4/2)^2 + (6/2)^2
x2 + 4x + (2)^2 + y2 + 6y + (3)^2 = 5 + (2)^2 + (3)^2
x2 + 4x + 4 + y2 + 6y + 9 = 5 + 4 + 9
(x + 2)2 + (y + 3)2 = 18

2x2 + 2y2 − 24x − 16y − 8 = 0
x2 + y2 − 12x − 8y − 4 = 0
x2 + y2 − 12x − 8y = 4
x2 − 12x + (-12/2)^2 + y2 − 8y + (-8/2)^2 = 4 + (-12/2)^2 + (-8/2)^2
x2 − 12x + (-6)^2 + y2 − 8y + (-4)^2 = 4 + (-6)^2 + (-4)^2
x2 − 12x + 36 + y2 − 8y + 16 = 4 + 36 + 16
(x − 6)2 + (y − 4)2 = 56

x2 + y2 + 2x − 12y − 9 = 0
x2 + y2 + 2x - 12y = 9
x2 + 2x + y2 - 12y = 9
x2 + 2x + (2/2)^2 + y2 - 12y + (-12/2)^2 = 9 + (2/2)^2 + (-12/2)^2
x2 + 2x + (1)^2 + y2 - 12y + (-6)^2 = 9 + (1)^2 + (-6)^2
x2 + 2x + 1 + y2 - 12y + 36 = 9 + 1 + 36
(x + 1)2 + (y − 6)2 = 46

7 0

4 years ago

PLEASE HELP ILL GIVE BRAINLY ITS ONLY ONE FRICKIN QUESTION

Radda [10]

Answer:

I think it's true

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

4. The sum of three consecutive odd integers is 36.

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