Answer:
The area of circle with radius half of original circle is 7 π cm² .
Step-by-step explanation:
Given as :
The Area of original circle = 28 π square centimeter
Let The radius of original circle = R
Let The area of circle with radius half of original circle = A square centimeters
Let The radius of circle with radius half of original circle = R'
Now, According to question
∵ Area of original circle = π × radius²
So, 28 π cm² = π × R²
Or, R² = 
Or, R² = 28 cm²
∴ R =
cm
i.e R = 2
cm
So, The radius of original circle = R = 2
cm
<u>Again</u>
∵ The radius of circle with radius half of original circle = R'
So, R' = 
i.e R' = 
∴ R' =
cm
So, The area of circle with radius half of original circle = π × R'²
i.e A = π × R'²
Or, A = π ×(
) ²
or, A = π × 7
So, The area of circle with radius half of original circle = 7 π cm²
Hence The area of circle with radius half of original circle is 7 π cm² . Answer
The answer to this question is <span>C. The student did not evaluate sqrt 16 and sqrt 25 before estimating sqrt 18.</span> The square roots of 16 and 25 are 4 and 5 respectively. He should have esimated that sqrt(18) is close to 4.2 instead of 17.
3 is the answer. I hope I helped you. Brainliest is appreciated.
Answer:
F ∪ H = {c, d, e, f, g, h}
F ∩ H = { }
Step-by-step explanation:
The union is the list of elements that are in either of the two sets.
F ∪ H = {c, d, e, f, g, h}
The intersection is the list of only those elements that appear in both sets. (There are none.)
F ∩ H = { } . . . . the empty set
Required expression is x/9 - 7