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lesya [120]
3 years ago
14

For less than twice a number K

Mathematics
2 answers:
wariber [46]3 years ago
6 0

Answer:

K>x>2

Step-by-step explanation:

X is a number of unknown

andriy [413]3 years ago
4 0

Answer:

kk

Step-by-step explanation:

kk cuz I say so ok cool nice

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The vertex of the parabola below is at the point (1.-3). Which of the equations below could be the one for this parabola?
Ilia_Sergeevich [38]

Answer: Choice D. y = (x-1)^2 - 3

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We have a = 1 as the leading coefficient.

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y = a(x-h)^2 + k

y = 1(x - 1)^2 + (-3)

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Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

AB=8

Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8

All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

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