All categories

3 years ago

I am learning to make meme what u think?

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

3 0

It’s great. Can I do all your homework?

Korvikt [17]3 years ago

3 0

Answer:

I like it, I think it's cute

Step-by-step explanation:

You might be interested in

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

4 years ago

Plzzzzz help 3 9/10 is the same as the sum of 3 1/3 and half of a number what is the number

kirill [66]

Answer:

9/10 = 1/3 + 1/2x

9/10 - 1/3 = 1/2x

LCM of 10 and 3 is 30

( 27 - 10)/30 = 1/2x

17/30 = 1/2x

17 * 2 = 30x

34=30x

34/30= 30x/30

x = 17/15

6 0

3 years ago

Am I right or wrong (don't answer the last one!)

S_A_V [24]

Answer:

1) Distributive Property of Multiplication (The terms are distributed)

2) Addition property of equality (Adding 14 to both sides)

3) Simplifying (We simplified the expression)

4) Division property of equality (Dividing both sides by 6)

6 0

3 years ago

Read 2 more answers

I ready diagnostic time!!

Dimas [21]

Answer:

I think choose (D)

$\frac{4}{10} and \frac{10}{25}$

5 0

3 years ago

the sum of ages of father and his son is 60 years.if the difference between their ages is 40 years then find the age of father a

cluponka [151]

Answer:

Father's age is 50, Son's age is 10

Step-by-step explanation:

X+Y=60

X-Y= 40

Let X represent the Father's age while Y represents the Son's age;

therefore, from the two equations, the value of X is

X= 60-Y

X= 40+Y then putting in the value of x

(40+Y) + Y= 60,

40+2Y=60

2Y=60-40 =20

Y= 10,

Now that we know the value of Y, we can get the value of x

If X+Y=60, then

X+10=60,

X=60-10,

X= 50

8 0

3 years ago

Read 2 more answers