Answer:
5/4k^2
Step-by-step explanation:
P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.
We will be using the following property of exponents:
\dfrac{a^x}{a^y}=a^{x-y}.
We have
P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.
Thus, the required product is \dfrac{5}{4k^2}.
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Answer:
B) 0.60n+1.48n = 176.80
Step-by-step explanation:
0.60 for every spiral wire per book = 0.60*n
0.74 per chipboard cover, 2 needed for each book = 1.48 per book = 1.48*n
Put it together: 0.60n+1.48n = 176.80
Solution:
<u>Convert the fractions into improper fractions and solve.</u>
- 9 1/2 ÷ 3 7/10
- => 19/2 ÷ 37/10
- => 19/2 x 10/37
- => 19 x 5/37
- => 95/37
<u>Convert the fraction into mixed fraction (Not required):</u>
- => 95/37 = 37/37 + 37/37 + 21/37
- => 1 + 1 + 21/37
- => 2 + 21/37
- => 2 21/37
The solution to the problem is 2 21/37.
