a and b are the two leg sides
c is the longest side.
a^2+b^2=c^2
a=x
b=9
c=11
a=c-b
11 squared is 121
9 squared is 81
121-81=40
The square root of 40, rounded to the nearest hundredth, is 6.32
The estimate of the sum of 202 and 57 is 260. You add the numbers together and than round up.
All you have to do is substitute the values in for y to see if they are true.
0: 9 ≤ 6 - 0 = 9 ≤ 6 (FALSE)
3: 9 ≤ 6 - 3 = 9 ≤ 3 (FALSE)
-3: 9 ≤ 6 - -3 = 9 ≤ 9 (TRUE)
-1: 9 ≤ 6 - -1 = 9 ≤ 7 (FALSE)
-6: 9 ≤ 6 - -6 = 9 ≤ 12 (TRUE)
6: 9 ≤ 6 - 6 = 9 ≤ 0 (FALSE)
-4: 9 ≤ 6 - -4 = 9 ≤ 10 (TRUE)
So, the values that belong to 9 ≤ 6 - y are -3, -4, and -6.
Answer:
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Step-by-step explanation:
To solve Az + 17 = -4z - b for z, we begin by combining like terms. We get:
Az + 4z = -b - 17, or z(A+4) = -(b+17).
Dividing both sides by (A+4), we get:
-(b+17)
z = --------------
A+4
