This is a question of resolving the forces in question into horizontal and vertical and then finding the action of the resultant force.
The first force acts at an angle less than 90° and thus its resolved forces are positive. The second force acts at angle larger than 90° and is incident and thus its horizontal value is positive while its vertical value is negative.
Therefore;
For force of 300 N at 30°;
Horizontal value = 300*Cos 30 = 259.81 N
Vertical value = 300*Sin 30 = 150 N
For 150 N at 135°;
Horizontal value = 150*Cos (180-135) = 106.07 N
Vertical value = -150*Sin (180-135) = -106.07 N
Then,
Resultant horizontal value = 259.81+106.07 = 365.88 N
Resultant vertical value = 150-106.07 = 43.93 N
Therefore,
Resultant force, v = Sqrt (365.88^2+43.93^2) = 368.51 N
Angle of action measured from horizontal = tan ^-1(43.93/365.88) 6.85°
Then,
v = 368.51 N at 6.85° from horizontal
The 3 consecutive integers are
n
n + 1
n + 2
Then
n2 + (n + 1)2 + (n + 2)2 = 194
n2 + (n2 + 2n + 1) + (n2 + 4n + 4) = 194
3n2 + 6n + 5 = 194
3n2 + 6n - 189 = 0
n2 + 2n - 63 = 0
(n - 7)(n + 9) = 0
n = 7 or -9
If n = 7, the 3 integers are 7, 8, and 9
If n = -9, the 3 integers are -9, -8, and -7
Mark brainliest please
Hope this helps you
Your answer be c/3
because it shows you 27 student
but it shows 2/3 of the students wearing sneakers
did this answer help
Answer:
40.38 Is the answer :)
Step-by-step explanation:
