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gulaghasi [49]
4 years ago
5

A bucket of paint has spilled on a tile floor. The paint flow can be expressed with the function r(t) = 3t, where t represents t

ime in minutes and r represents how far the paint is spreading.
The flowing paint is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2.

Part A: Find the area of the circle of spilled paint as a function of time, or A[r(t)]. Show your work. (6 points)

Part B: How large is the area of spilled paint after 10 minutes? You may use 3.14 to approximate π in this problem. (4 points)
Mathematics
1 answer:
Anika [276]4 years ago
7 0
R(t) = 3t ; where t represents the time in minutes and r represents how far the paint is spreading.
A(r) = πr²

Part A: 
A[r(t)] = π (3t)² = 3.14 * 9t² = 28.26t²

Part B:
r(10) = 3(10) = 30
A(r) = 3.14 * 30² = 3.14 * 900 = 2,826 square unit

Hope This Helped! :3
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Find the 53rd term of the arithmetic sequence -12, -1, 10
RSB [31]

440 is the answer

Tn=a+(n-1)d

Tn=53

a= -12

n=53

d= 11

-12+(53-1)11 = 440

5 0
3 years ago
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If v is one-third of the quantity 3 less than u, how does v change if u is increasing?
kykrilka [37]

Answer:

v increases when u increases

Step-by-step explanation:

From the question, we have that

v = u - \frac{1}{3} * 3

v = u - \frac{3}{3}

v = u - 1

Take u = 1

v = u - 1

v = 1 - 1

v = 0

Take u = 2

v = u - 1

v = 2 - 1

v = 1

Take u = 10

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v = 10 - 1

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<em>This implies that an increment in u brings an increment in v</em>

3 0
3 years ago
For Tran thank you appreciate it
Anestetic [448]

Step-by-step explanation:

Let alpha be the unknown angle. We can set up our sine law as follows:

\frac{ \sin( \alpha ) }{5 \: m}  =  \frac{ \sin(42) }{3.6 \: m }

or

\sin( \alpha )  =  \frac{5 \: m}{3.6 \: m} \times  \sin(42)  = 0.929

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3 0
3 years ago
On a typical long distance call you talk for 30 minutes. On a typical local call you talk for 10 minutes. Your phone company off
klio [65]

The number of long distance calls to be made can be obtained by linear programming

  • To minimize the phone bill, the number of long distance call to be made is none

Reason:

Maximum number of number of long distance calls = 15

Maximum number of local calls = 30

Number of minutes of calls to make each month = 240 minutes

Duration of each long distance call = 30 minutes

Duration of each local call = 10 minutes

Cost of long distance call = $0.08

Cost of local call = $0.03

Solution:

Let <em>X</em>, represent the number of long distance calls, and let <em>Y</em> represent the number local calls

The objective function is given as follows;

  • P = 0.08·(30)·X + 0.03·(10)·Y

P = 2.4·X + 0.3·Y

The constraints are;

X ≥ 0

Y ≥ 0

X ≤ 15

Y ≤ 30

30·X + 10·Y ≥ 240

Solving we have;

  • Y ≥ 24 - 3·X

The above inequality can be plotted with MS Excel

From the objective function, P = 2.4·X + 0.3·Y, the coefficient of the long

distance calls, <em>X</em> is larger than the coefficient of the local calls <em>Y</em>, therefore,

making the minimum possible number of long distance calls of 0, and 24

local calls will give a cost;

  • P = 2.4 × 0 + 0.3 × 24 = 7.2

Therefore, to minimize the phone bill, the number of long distance calls to

be made is <u>zero long distance calls</u>

Learn more about linear optimization here:

brainly.com/question/21491539

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A retirangle has an area of 40 units.the lenght is 6 units greater then the width
slega [8]
40 units multiply by 6 units equal 240 units

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