Answer:
sorry I don't know
Step-by-step explanation:
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Answer:
the cyclists rode at 35 mph
Step-by-step explanation:
Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then
distance= speed*time
since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :
time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train
thus denoting v as the speed of the cyclists :
7/8*L / v = L / 40 mph
v = 7/8 * 40 mph = 35 mph
v= 35 mph
thus the cyclists rode at 35 mph
I will show you the steps on how you get that answer and if you have any questions after that let me know and I'd be more than happy to help answer them for you.
The first step for solving (1 + y)² is to use the equation (a + b)² = a² + 2ab + b² to expand the expression.
1² + 2 × 1y + y²
1 raised to any power equals 1,, so remove the power.
1 + 2 × 1y + y²
Calculate the product of 2 × 1y.
1 + 2y + y²
Finally,, use the commutative property to reorder the terms.
y² + 2y + 1
Let me know if you have any further questions.
:)
For 33 Hours, It is = $252.45
Now, for 1 Hour, It is 252.45 / 33 = 7.65
Now, For 36 hours, It would be: 7.65 * 36 = 275.4
In short, Your Answer would be: $275.4
Hope this helps!
Given:
To find:
Solution:
Putting the equation (i) value into equation (ii):
Putting the value of (d) into equation (i):
Calculating the 
Formula:
![\bold{S_n = \frac{n}{2}[2a + (n - 1)d ] }\\](https://tex.z-dn.net/?f=%5Cbold%7BS_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n%20-%201%29d%20%5D%20%7D%5C%5C)
Calculating the 
![\to \bold{S_{10} = \frac{10}{2}[2\frac{10}{3} + (10- 1)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + (9)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 9 \times \frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 3\times 5 ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 15 ] }\\\\\to \bold{S_{10} = 5[\frac{20+ 45}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{65}{3} ] }\\\\\to \bold{S_{10} = 5 \times \frac{65}{3} }\\\\\to \bold{S_{10} = \frac{325}{3} }\\\\\to \bold{S_{10} =108.33 }](https://tex.z-dn.net/?f=%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%20%5Cfrac%7B10%7D%7B2%7D%5B2%5Cfrac%7B10%7D%7B3%7D%20%2B%20%2810-%201%29%5Cfrac%7B5%7D%7B3%7D%20%5D%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%205%5B%5Cfrac%7B20%7D%7B3%7D%20%2B%20%289%29%5Cfrac%7B5%7D%7B3%7D%20%5D%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%205%5B%5Cfrac%7B20%7D%7B3%7D%20%2B%209%20%5Ctimes%20%5Cfrac%7B5%7D%7B3%7D%20%5D%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%205%5B%5Cfrac%7B20%7D%7B3%7D%20%2B%203%5Ctimes%205%20%5D%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%205%5B%5Cfrac%7B20%7D%7B3%7D%20%2B%2015%20%5D%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%205%5B%5Cfrac%7B20%2B%2045%7D%7B3%7D%20%5D%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%205%5B%5Cfrac%7B65%7D%7B3%7D%20%5D%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%205%20%5Ctimes%20%5Cfrac%7B65%7D%7B3%7D%20%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D%20%20%5Cfrac%7B325%7D%7B3%7D%20%20%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7BS_%7B10%7D%20%3D108.33%20%7D)
Therefore, the final answer is " 
"
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