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3 years ago

Please help me thank you and show work

Mathematics

2 answers:

Tamiku [17]3 years ago

6 0

Answer:

m=-18

Step-by-step explanation:

6m=-108

m=-108/6

m=-18

Alinara [238K]3 years ago

5 0

Answer:

okay so the answer is -18

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1/7 of all students achieved great success in the written exercise in mathematics. 3/7 very good success. 2/7 good success, whil

laila [671]

Answer:

x = 28

Step-by-step explanation:

Let the total number of students = x

x/7 + 3x/7 + 2x/7 + 4 = x If that is all there is. If it isn't the problem can't be done. Combine like terms.

x(1 + 3 + 2)/7 + 4 = x

x (6/7) + 4 = x Subtract 6x/7 from both sides

4 = x - 6x/7

4 = 7x/7 - 6x/7 Combine

4 = 1/7x Multiply both sides by 7

4*7 = 7x / 7

x = 28

6 0

2 years ago

Someone please help.

Leokris [45]

Answer:

See explanation

Step-by-step explanation:

1 = b (0,-2)

2 = b (0,1)

6 = a (3,0)

7 = a (-2,2)

4 0

3 years ago

Read 2 more answers

Find the correct sum of the polynomials (6x3 − 8x − 5) + (3x3 + 6x + 2).

Advocard [28]

Answer:

$9x^3-2x-3$

Step-by-step explanation:

The question is

$(6x^3-8x-5)+(3x^3+6x+2)\\$

collect like terms

$(6x^3-8x-5)+(3x^3+6x+2)\\\\\\6x^3+3x^3-8x+6x-5+2\\\\\\9x^3-2x-3$

3 0

3 years ago

Can someone help me pls

Wittaler [7]

Answer:

3 cm

Step-by-step explanation:

$V_{cylinder} = 189\pi \: cm^3$ (Given)

$h_{cylinder} = 21\: cm$ (Given)

Formula for $V_{cylinder}$ is given as:

$V_{cylinder} = \pi r^2h$

$\implies 189\pi = \pi r^2(21)$

$\implies \frac{ 189\pi}{21\pi} = r^2$

$\implies 9 = r^2$

$\implies \pm\sqrt 9 = r$

$\implies \pm 3 = r$

Length of radius can not negative

$\implies r = 3 \: cm$

Hope it helps you in your learning process.

8 0

2 years ago

Read 2 more answers

Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5). Describe the ste

olga_2 [115]

1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.

2. So f(x)= $(x-a)^{3}$

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:

$f(x)=b(x-a)^{3}$

4. Now, f(0)=-5 so $-5=f(0)=b(0-a)^{3}=b(-a) ^{3}=-ba ^{3}$

$-5=-ba ^{3}$

$5=ba ^{3}$

$b= \frac{5}{ a^{3} }$

5. the function is $f(x)=\frac{5}{ a^{3} }(x-a)^{3}$ where a can be any real number except 0

7 0

4 years ago

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