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s2008m [1.1K]
3 years ago
9

Evaluate the expression 2l+2w for I=5.7 and w=6.2

Mathematics
1 answer:
inessss [21]3 years ago
5 0

Answer:

23.8

Step-by-step explanation:

2(5.7) + 2(6.2)

11.4 + 12.4

23.8

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A group spends $277.50 to rent a total of 15 tubes. How many of each type of tube does the group rent?
tensa zangetsu [6.8K]

The amount spent on each tube is $18.5

The total amount spent to rent 15 tubes by the group is $277.50.

Since they did not specify in the question the types of tubes they rented, we cannot determine each types of tubes that the group rented but we can determine the amount spent on each tube provided that they are all the same types.

∴

if 15 tubes = $277.50

1 tube = $x

By cross multiplying:

\mathbf {\$(x) = \dfrac{ \$277.50 \times 1 \ tube }{15 \ tube}}

\mathbf {(x) = \$18.5}

Therefore, we can conclude that the amount spent on each tube is $18.5

Learn more about arithmetic operations here:

brainly.com/question/15385899?referrer=searchResults

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3 years ago
Great deal of work to do. Which word is the closest meaning to the underlined word
GarryVolchara [31]
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3 years ago
The quotient of a number and -9 increased by 10 is 11.
andrezito [222]
So the division of a number and -9 or
x/-9

+10=11 or

(x/-9)+10=11
subtract 10 from both sides
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3 0
3 years ago
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Please help with imaginary numbers worksheet!
mihalych1998 [28]

Problem 5

<h3>Answer:   6i</h3>

------------------

Explanation:

We have these four identities

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

<h3>Answer:  -3i</h3>

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\

=============================================

Problem 7

<h3>Answer:   -1</h3>

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1

=============================================

Problem 8

<h3>Answer:    -1 + i</h3>

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i

8 0
2 years ago
Read 2 more answers
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