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Svetllana [295]
2 years ago
11

Which two statements are missing in steps 3 and 4?

Mathematics
2 answers:
mr Goodwill [35]2 years ago
8 0

Answer:

answer is b on edge

Step-by-step explanation:

Snezhnost [94]2 years ago
4 0

Answer:

∠B ≅ ∠Y △ABC ~ △ZYX by the SAS similarity theorem.

Step-by-step explanation:

1. AB=6 units

YZ=3 units

BC=8 units

XY=4 units, then

\dfrac{AB}{ZY}=\dfrac{BC}{YX}=2

2. \angle B and \angle Y are right angles - given

3.  \angle B\cong \angle Y two right angles are always congruent.

4. \triangle ABC\sim \triangle ZYX by SAS similarity theorem.

SAS Similarity Theorem states that if two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.

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If y-18=14, what is the value of 2(y+9)?
stealth61 [152]
------------------------------------------------------------------------
Find the value of y
------------------------------------------------------------------------
y  - 18  =  14
   + 18     + 18

y  =  32
------------------------------------------------------------------------
substitute y = 32 into 2 (y + 9) 
------------------------------------------------------------------------

2( y + 9 ) = 2 ( 32 + 9 )
2 (y + 9 ) = 2 (41)
2 ( y + 9 ) = 82

------------------------------------
Answer: 82
------------------------------------


5 0
3 years ago
Read 2 more answers
​Cameron, Arthur, and Jamie are playing soccer. Their locations are recorded by a motion tracking system. The grid shows distanc
Luden [163]

Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{2500+400}

\text{Distance between Cameron and Arthur}=\sqrt{2900}

\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54

Therefore, the distance Arthur is about 54 meters away from​ Cameron.

2. Let us find the distance between Cameron and Jamie.

\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}

\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}

\text{Distance between Cameron and Jamie}=\sqrt{625+2500}

\text{Distance between Cameron and Jamie}=\sqrt{3125}

\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56

Therefore, Jamie is about 56 meters away from​ Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.


4 0
3 years ago
Read 2 more answers
A plumber charges $80 for a house call and $25 per hour for his services. Which of the following is a linear model of his charge
blsea [12.9K]

Answer:bals

Step-by-step explanation:25(number of hours worked) +80$ for initial charge

6 0
3 years ago
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Chords DB and MN intersect at the center of circle MBND. Which is the measure of the minor arc DM
IRINA_888 [86]

Answer:

90

Step-by-step explanation:

DM=1/4 of MBND

a circle =360

360÷4=90

6 0
3 years ago
Given: Point K is between H and J, HK = x - 5, KJ = 5x-12, and HJ = 25. Find the value of x
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