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cestrela7 [59]
3 years ago
9

Find the expected value and the variance of the number of times one must throw a die until the outcome 1 has occurred 5 times.

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

Answer: E(X) = 30; Var[X] = 180

Step-by-step explanation: This is a <u>Bernoulli</u> <u>Experiment</u>, i.e., the experiment is repeated a fixed number of times, the trials are independents, the only two outcomes are "success" or "failure" and the probability of success remains the same, So, to calculate <em><u>Expected</u></em> <em><u>Value</u></em>, which is the mean, in these conditions:

E(X)=\frac{r}{p}

r is number of times it is repeated

p is probability it happens

Solving:

E(X)=\frac{5}{1/6}

E(X) = 30

<u>Variance</u> is given by:

Var[X]=\frac{r(1-p)}{p^{2}}

Var[X]=\frac{5(1-1/6)}{(1/6)^{2}}

Var[X]=5.\frac{5}{6}.6^{2}

Var[X] = 180

Expected Value and Variance of the number of times one must throw a die until 1 happens 5 times are 30 and 180, respectively.

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Answer:

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equation A and equation B are equal

therefore

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