To get a perpendicular line, your slopes will equal -1 when multiplied...this means if we multiply - 4 x (1/4), we get out slope to use for the next step.
Y - Y1 = M(X - X1) passes through (-2, 7)
Y - 7 = 1/4(X - (-2))
Y - 7 = 1/4(X + 2)
Y - 7 = 1/4X + 1/2
+7 + 7
Y = 1/4X + 7.5
M∠ADB + m∠BDC = m∠ADC [<span>angle addition postulate]
x + x + 10 = 60
2x + 10 = 60
2x = 60 - 10
2x = 50
x = 50/2
x = 25
a
m</span>∠ADB = x = 25°
b
m∠BDC = x + 10 = 25 + 10 = 35°
Answer: 12.
To solve this problem, let's first solve for x. Thi is easiest done by figuring what QR is in terms of x using two equations, both from different lines.
In the first line: QR = 15 - 4x.
In the third line:QR = 13x - 1 - x = 12x - 1.
Now, we have to set these equations equal to each other. 15 - 4x = 12x - 115 = 16x - 116x = 16x = 1
Next, we take line three, 13x - 1, and substitute x as 1. The answer is 12.
Answer:
The equations represent circles that result in the same graph.
Step-by-step explanation:
we have

Divide by -10 both sides
-----> equation A
This is the equation of a circle centered at origin with radius 
and
Divide by 5 both sides
-----> equation B
This is the equation of a circle centered at origin with radius 
equation A and equation B are equal
therefore
The system has infinite solutions, because the equations represent circles that result in the same graph.
F x (x + h) - fx/h
fx +fh - fx /h
fh/h
f
So f is the answer