The area of triangle ABC from the given vertices is gotten as; 7.5
<h3>How to find the area of a triangle?</h3>
We are given the vertices of the triangle as;
A(1, 2)
B(4, 0)
C(1,-4)
The formula for area of a triangle with 3 vertices is;
Area = ¹/₂[x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]
Thus;
Area = ¹/₂[1(0 + 4) + 4(-4 - 1) + 1(1 - 0)]
Area = ¹/₂(4 - 20 + 1)
Area = -7.5
Read more about area of triangle at; brainly.com/question/17335144
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Theorem of Pythagoras: a²+b²=c², where a, b is legs and c is hypotenuse.
We've got one leg known, let it be a=sqrt 3,
and the hypotenuse - c=2sqrt3
Putting these into the theorem, we get an equation: (sqrt3)²+b²=(2sqrt3)² . Solving it, we get:
3+b²=4*3
3+b²=12
b²=9
This equation has two possible roots: b=3 and b=-3. Since this is a triangle, there can't be a side with a negative value => b=3.
The answer is a. 3
John sold 30U
Rick sold 25U
So, Rick sold 5 fewer units than John.
Hope that helps.
Answer:
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Step-by-step explanation:
If you look at a number line and look to the left you can see that -11 it is at the end and -8 is at the begging
Multiplicative inverse makes the numver 1 so it multiplies by 1 which cancles the number
examle
1/3x=10
to make 1/3 into 1
we multiplyu it by its mutlipcative invers which is 3/1
1/3 times 3/1=3/3=1
1/3x times 3/1=3/1 times 10
1x=30
additive inverse makes the number 0 to cancel it out
so example
x+3=10
add the inverse of 3 to make it 0
inverse of 3 is -3
3+-3=0
so x+3-3=10-3
x+0=7
x=7