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balandron [24]
2 years ago
7

The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisions organized

by age groups.
Baseball League (B) Softball League (S) Ages 7 – 9 (X) 3 7 Ages 10 – 12 (Y) 2 2 Ages 13 – 15 (Z) 1 1 If the winner is in Baseball League, find the probability that the winning team is in either the Ages 10 - 12 division or the Ages 13 - 15 division. Answer in terms of a reduced fraction.

A. P(Y | B) = a0 a1

B. P(Z | B) = a2 a3

C. P(Y or Z |B) = a4 a5
Mathematics
1 answer:
castortr0y [4]2 years ago
4 0

Answer:


Step-by-step explanation:

heyq


The correct answer is:


7/10


Explanation:


Finding the totals of each column and row, we find:


There are 3+2+1 = 6 children in the baseball league.

There are 7+2+1 = 10 children in the softball league.

There are 3+7 = 10 children in the 7-9 division.

There are 2+2 = 4 children in the 10-12 division.

There are 1+1 = 2 children in the 13-15 division.

There are a total of 10+6 = 16 children.


We start with the information that the team is a member of the softball league.  There are 10 children in this league; this is the denominator of the probability.


There are 7 children in the 7-9 division that are in the softball league.  This gives us the probability 7/10.

please you are a student study well especially graph is easy thing to do.


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8 0
2 years ago
Mark has 17 coins that are dimes and quarters. The total value of the coins is $2.45. How many dimes does mark have?
seropon [69]

Answer: 12 dimes and 5 quarters

Step-by-step explanation: Let's start this problem by setting up a chart so we can organize our information that we're given in this problem.

Down the left side, we'll have our different types of coins. In this case dimes and quarters. Across the top we'll have our formula which is shown below.

Number of coins · value of each coin = total value

Now let's fill out our chart.

For number of dimes and quarters, we know that mark has a total of 17 dimes and quarters but we don't know how many of each he has. In fact, that's what the problem is asking.

So if we represent our number of dimes as <em>x</em>, we can call our number of quarters <em>17 - x</em>.

The value of each dime is 10¢ and the value of each quarter is 25¢.

Our total value based on our formula is going to come from the first column times the second column. So the total value of our dimes is <em>x times 10</em> or <em>10x </em>and the total value of our quarters is <em>17 - x times 25</em> or <em>25 (17 - x)</em>.

Our goal in this problem will be to find <em>x </em>because <em>x</em> represents our number of dimes and the problem asks how many dimes does he have. If we know the number of dimes, we can easily find the number of dimes and we'll have our answer. However, we need an equation in order to find <em>x</em>.

It's important to understand that he information in this equation will always come from the last column of your chart, the total value column. So what do we know about the total value of our dimes and the total value of our quarters?

Well we know that the total value of all of our coins is $2.45. So if we add the total value of our dimes + the total value of our quarters, that should equal $2.45. So below the chart I added an additional box and I put 245 in it. Notice that I wrote 245 in terms of cents because our value of dimes and value of quarters is also written in terms of cents and we need to be constient.

So here's our equation.

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If we solve this, we get <em>x = 12</em>.

Going back up into our chart, remember that <em>x</em> represents our number of dimes so Mark has 12 dimes. To get his number of quarters, we take 17 - x which is 17 - 12 or 5 quarters and that's our answer.

I have also attached the chart that I have made below.

7 0
2 years ago
The first discount on a camera was 18%. The second discount was 20%. After these two discounts the price was $328. What was the
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Answer:

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Step-by-step explanation:

We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.

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20% off means we paid 80%. We know we paid $328 of some price.

\frac{80}{100} =\frac{328}{y}

I can now cross-multiply by multiplying numerator and denominator from each ratio.

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I can now cross-multiply by multiplying numerator and denominator from each ratio.

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I now solve for y by dividing by 82.

\frac{82y}{82} =\frac{41000}{82} \\y= $500

The original price was $500.


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8 0
3 years ago
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