Okay, so let's go over multiplying negative numbers. A positive times a positive is a positive, right? But a negative times a negative is also a positive. Only a negative times a positive (or a positive times a negative) gives you a negative number. So, we know that one of our 2 numbers in this question must be negative; the other must be positive.
Let's now take a look at the factors of -147, starting with the positives. Obviously, -147 and 1 are factors: -147 * 1 = -147. What other factors of -147 are there?
What about 7? Try it: -147 / 7 = -21. So here are two factors: -21, and 7. They multiply to -147. Do they add up to -14? Let's see: -21+7 = 7+(-21) = 7-21= -14. Yup, that works!
Answer: -21 and 7
Answer:
Since there are 4 green bars for every 3 red bars and we are trying to find the number of red bars if there are 200 green bars, we can create the ratio:
4
x
:
3
y
Where x is equal to the number of green bars and y
is the number of red bars.
We know the number of green bars is equal to 200, so we can divide it by 4, giving us:
200
/4=50
Then we can solve for y
, the number of red bars.
// Multiple y by 50
3
⋅
50
=
150
So for every 4 green bars, there are 3 red bars.
For every 200 green bars, there are 150 red bars
Step-by-step explanation:
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You are given two points in the linear function. At time 0 years, the value is $3000. At time 4 years, the value is $250. This means you have points (0, 3000) and (4, 250). You need to find the equation of the line that passes through those two points.
y = mx + b
m = (y2 - y1)/(x2 - x1) = (3000 - 250)/(0 - 4) = 2750/(-4) = -687.5
Use point (0, 3000).
3000 = -687.5(0) + b
b = 3000
The equation is
y = -687.5x + 3000
Since we are using points (t, v) instead of (x, y), we have:
v = -687.5t + 3000
Answer: d. v = -687.50 t + 3,000
Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
