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Arlecino [84]
2 years ago
8

I WILL GIVE BRANLIST

Computers and Technology
2 answers:
solniwko [45]2 years ago
8 0
Center alignment idk lol
qaws [65]2 years ago
4 0

Answer:

space alignment

Explanation:

I'm not sure just taking a guess cuz I'm bored lol

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Create a program that includes a function called toUpperCamelCase that takes a string (consisting of lowercase words and spaces)
astraxan [27]

Answer:

#include<iostream>

using namespace std;

//method to remove the spaces and convert the first character of each word to uppercase

string

toUpperCameICase (string str)

{

string result;

int i, j;

//loop will continue till end

for (i = 0, j = 0; str[i] != '\0'; i++)

{

 if (i == 0)       //condition to convert the first character into uppercase

  {

  if (str[i] >= 'a' && str[i] <= 'z')   //condition for lowercase

  str[i] = str[i] - 32;   //convert to uppercase

  }

if (str[i] == ' ')   //condition for space

  if (str[i + 1] >= 'a' && str[i + 1] <= 'z')   //condition to check whether the character after space is lowercase or not

  str[i + 1] = str[i + 1] - 32;   //convert into uppercase

if (str[i] != ' ')   //condition for non sppace character

  {

  result = result + str[i];   //append the non space character into string

  }

}

//return the string

return (result);

}

//driver program

int main ()

{

string str;

char ch;

//infinite loop

while (1)

{

fflush (stdin);

//cout<< endl;

getline (cin, str);   //read the string

//print the result

//cout<< endl << "Q";

// cin >> ch; //ask user to continue or not

ch = str[0];

if (ch == 'q' || ch == 'Q')   //is user will enter Q then terminatethe loop

  break;

cout << toUpperCameICase (str);

cout << endl;

}

return 0;

}

8 0
3 years ago
In addition to developing sketches, computer-aided design programs are used by fashion designers to perform which task?
nikdorinn [45]

Answer:

flat drawing, pattern making development, computerized marker planning and many other fashion designing related aspects.

Explanation:

6 0
2 years ago
Write a method called all Less that accepts two arrays of integers and returns true if each element in the first array is less t
GaryK [48]

Answer:

The program to this question can be given as:

Program:

#include<iostream> //header file

using namespace std; //using name space

bool allLess (int arr1[], int arr2[]) //defining method allLess  

{

int a,b; //define variable

a=  *(&arr1 + 1) - arr1; //hold length of arr1

b=  *(&arr2 + 1) - arr2; //hold length of arr2

if(a!=b) //checking condition  

{

return 1; //return value

}

for(int i=0; i<a; i++) //loop

{

if( arr1[i]>=arr2[i]) //checking condition

{

return 1; //return value

}

}

return 0; //return value

}

int main() //define main method.

{

   int arr1[]={1,2,3,4,5}; //define array arr1 and assign value.

   int arr2[]={4,5,6,7,8}; //define array arr2 and assign value.

   cout<< allLess(arr1,arr2); //function calling

   return 0;

}

Output:

1

Explanation:

The Explanation of the C++ language program can be given as follows:

  • In the above program firstly we include the header file. Then a method is defined that is "allLess" this method accepts two arrays that are "arr1 and arr2". This function returns a boolean value that is true or false.
  • Inside a function, we define a conditional statement and a loop in the if block we check the length of the arr1 array variable is not equal to arr2 array length. if this condition is true it will return false.
  • In the loop, we define another if block in this block we check that if arr1 array elements are grater then equal to arr2 array element if this condition is true it will return false. At the end of both if block and loop the function will return a value that is "true".
  • In the main method, we define two arrays and pass to the function and use (cout function) for print return value.
8 0
3 years ago
Use python
Degger [83]

Answer:

def rec_dig_sum( num ):

   num_list = [ digit for digit in str(num)]

   total = 0

   for x in num_list:

       total += x

   return total

def dict_of_rec_dig_sums(low, high):

   mydict = dict()

   for number in the range(low, high+1):

      mydict[rec_dig_sum(number)] = number

   return mydict

Explanation:

The python program defines two functions, "rec_dig_sum" and "dict_of_rec_dig_sums". The former accepts a number and returns the sum of the digits of the number while the latter accepts a low and high number range.

The program returns a dictionary with the recursive sum as the keys and the number count as the values.

3 0
3 years ago
(BRAINLIEST QUESTION!!!)
docker41 [41]

Answer:

Possible if hackers are not so intelligent.

Explanation:

Actually, hackers are intelligent

where they will change location code in different places every second. So end-user who is trying to trace it he or she has to use their intelligence to find the exact location of hackers.

Normally hackers will generate different location places and by using decipher it is possible to find the location codes.

Since hackers used encrypted message we need to decrypts the message and find it out and understand the decrypt and encrypt technology used by hackers.

It is possible to by using decipher to get uncovered locations

4 0
3 years ago
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