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3 years ago

14

What is the complete factorization of 36y2 − 1?

1 answer:

stiv31 [10]3 years ago

4 0

Answer:

(6y+1)(6y-1)

Step-by-step explanation:

Difference of square (You may want to search it up if you want to learn more)

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What is the solution to the compound inequality 3x-8>-5 and 2x-7<5

-BARSIC- [3]

Answer:

<h2>1 < x < 6 ⇒ x ∈ (1, 6)</h2>

Step-by-step explanation:

3x - 8 > -5 <em>add 8 to both sides</em>

3x > 3 <em>divide both sides by 3</em>

x > 1

2x - 7 < 5 <em>add 7 to both sides</em>

2x < 12 <em>divide both sides by 2</em>

x < 6

From x > 1 and x < 6 we have the solution 1 < x < 6 ⇒ x ∈ (1, 6)

6 0

3 years ago

What 15 by 15 I need to know!!

Colt1911 [192]

15 times 15 = 225. :) since i helped you, can you help me? My question: <span>brainly.com/question/2967131</span>

7 0

3 years ago

Read 2 more answers

PLEASE HELP!!!! ASAP!!!!!

SCORPION-xisa [38]

-6 5 -3 is the corrdante did those sir

8 0

2 years ago

The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

$a_n=a_1(r)^{n-1}$

where $a_1=15$ and $a_5=\frac{243}{125}$

For $n=5$ , we have,

$\frac{243}{125}=15(r)^4$

Simplifying, we have,

$r=\frac{3}{5}$

Thus, the common difference is $r=\frac{3}{5}$

Now, we shall find the 2nd, 3rd and 4th terms by substituting $n=2,3,4$ in the formula $a_n=a_1(r)^{n-1}$

For $n=2$

$a_2=15(\frac{3}{5} )^{1}$

$=9$

Thus, the 2nd term of the sequence is 9

For $n=3$ , we have,

$a_3=15(\frac{3}{5} )^{2}$

$=15(\frac{9}{25} )$

$=\frac{27}{5}$

Thus, the 3rd term of the sequence is $\frac{27}{5}$

For $n=4$ , we have,

$a_4=15(\frac{3}{5} )^{3}$

$=15(\frac{27}{25} )$

$=\frac{81}{25}$

Thus, the 4th term of the sequence is $\frac{81}{25}$

Therefore, the geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

5 0

3 years ago

I need help on 9. 10. 11.

netineya [11]

9. there are 22 signs
10. 34.46 square miles
11. 77.9 miles
:)

8 0

3 years ago