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1 year ago

PLEASE HELP!!!!!! 20 POINTS

Mathematics

1 answer:

Mars2501 [29]1 year ago

6 0

The graph which has the same end behaviour as the function given; f(x) = (10x³+x² +3)/(2x²+1) is; a linear graph whose slope is 5.

<h3>Which graph has the same end behaviour as the function given?</h3>

The function given can further be simplified by means of polynomial division in which case;

although not a perfect division; the quotient of the division is; (5x-0.5) and evidently, the function which would have the same end behaviour as the given function is a linear function whose slope is 5.

Read more on graph of functions;

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Amanda needs to cut a board to use for a project. The board is 10 feet long. She first has to cut off 1 3/4 feet from one end of

kirza4 [7]

4x+1 3/4=10 because the 1 3/4 doesn’t have an x since it is not a variable but rather a constant.

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2 years ago

A triangle has side lengths of 7 inches, 12 inches, and c inches. Enter values to write an inequality that describes the possibl

Leokris [45]

Answer:

The inequality is: 5<c<19

Length of third side "c" can have values greater than 5 but less than 19

Solution:

Given that,

Length of two sides of triangle are 7 inches and 12 inches respectively

Let the length of third side be "c"

The Triangle Inequality Theorem, states that, the sum of the lengths of any two sides of a triangle is greater than the length of the third side

So we get a inequality as:

Case 1:

Sum of length of two sides of triangle > length of third side

Rewrite,

Case 2:

Let 12 inches be the length of third side

Sum of sides of length 7 and c > 12

Therefore from case 1 and case 2,

Which can be combined,

Therefore the possible values of "c" are:

"c" can have values greater than 5 but less than 19

6 0

2 years ago

6km in 2 hours as a rate in simplest form

Brrunno [24]

6km in 2 hours =

6/2 = 3

so 3 km per hour

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3 years ago

Traffic flow is traditionally modeled as a Poisson distribution.A traffic engineer monitors the traffic flowing through an inter

babymother [125]

Answer:

There is a 6.07% probability that during next 2 min exactly 5 cars passing an intersection are from state.

Step-by-step explanation:

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

A traffic engineer monitors the traffic flowing through an intersection with an average of 6 cars per minute. So in 2 minutes, 12 cars are expected to flow through the intersection.

If 75% of vehiclesare from state, what is the probability that during next 2 min exactly 5 cars passing an intersection are from state?

We want to know how many of these cars are from state. In 2 minutes, 0.75*12 = 9 cars from the state are expected to pass the intersection, so $\mu = 9$ .

We want to find P(X = 2).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 5) = \frac{e^{-9}*9^{5}}{(5)!} = 0.0607$

There is a 6.07% probability that during next 2 min exactly 5 cars passing an intersection are from state.

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3 years ago

When doctors prescribe medicine, they must consider how the drug’s effectiveness declines as time passes. If each hour a drug is

Dima020 [189]

Answer:

The total time for the initial dose of 500 mg to reach a level of 150 mg is approximately 11 hours and 27 minutes

Step-by-step explanation:

Initial dose = 500 mg

Let's calculate the effectiveness of the drug hour by hour, this way:

After 1 hour: 90% of 500 = 450 mg

After 2 hours: 90% of 450 = 405 mg

After 3 hours: 90% of 405 = 364.5 mg

After 4 hours: 90% of 364.5 = 328.05 mg

After 5 hours: 90% of 328.05 = 295.25 mg

After 6 hours: 90% of 295.25 = 265.73 mg

After 7 hours: 90% of 265.73 = 239.16 mg

After 8 hours: 90% of 239.16 = 215.24 mg

After 9 hours: 90% of 215.24 = 193.72 mg

After 10 hours: 90% of 193.72 = 174.35 mg

After 11 hours: 90% of 174.35 = 156.92 mg

After 12 hours: 90% of 156.92 = 141.23 mg

Difference between 11 and 12 hours: 156.92 - 141.23 = 15.7 mg

Difference per minute between 11 and 12 hours: 15.7/60 = 0.262 mg

Time to reach a level of 150 mg in minutes after 11 hours = (156.92-150)/0.262

Time to reach a level of 150 mg in minutes after 11 hours = 26.4

The total time for the initial dose of 500 mg to reach a level of 150 mg is approximately 11 hours and 27 minutes

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3 years ago