How many combinations with repetition are allowed if n = 5 and r = 3? 120 125 10 35

2 answers:

joja [24]2 years ago

8 0

Answer:

Step-by-step explanation:

Since repetition is allowed, we use the equation

((n+r-1)!/(r!(n-1)!) = 7!/(3!x4!) = 35

Aneli [31]2 years ago

5 0

10 possible combinations

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