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IrinaVladis [17]
2 years ago
10

How many combinations with repetition are allowed if n = 5 and r = 3? 120 125 10 35

Mathematics
2 answers:
joja [24]2 years ago
8 0

Answer:

35

Step-by-step explanation:

Since repetition is allowed, we use the equation

((n+r-1)!/(r!(n-1)!) = 7!/(3!x4!) = 35

Aneli [31]2 years ago
5 0
10 possible combinations
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Graph the hyperbola using the transverse axis, vertices, and co-vertices:
Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

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The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

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Evaluate the quotient

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This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

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So, we have:

(0 - 3, 0) and (0 + 3, 0)

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(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

#SPJ1

4 0
1 year ago
Solve for x<br> 1 7 1<br> 2<br> х<br> Your answer
ki77a [65]

Answer:

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add 5 to the -5 so it cancels itself out. then add the 5 to 7 so it become 12. the you have 3x = 12

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