Question

Refer to the following unbalanced equation:

Answer 1

Mass of Oxygen (O₂) : = 88.16 g

Further explanation

Given

Reaction(unbalanced)

C₆H₁₄+ O₂ → CO₂ + H₂0

25 g C₆H₁₄

Required

mass of oxygen (O₂)

Solution

Balanced equation

2C₆H₁₄ + 19O₂ ⇒12 CO₂ + 14 H₂O

mol C₆H₁₄ (MW=86,18 g/mol) :

= mass : MW

= 25 g : 86.18 g/mol

= 0.29

From the equation, mol ratio of C₆H₁₄ : O₂ = 2 : 19, so mol O₂ :

= 19/2 x mol C₆H₁₄

= 19/2 x 0.29

= 2.755

Mass O₂(MW=32 g/mol) :

= 2.755 x 32

= 88.16 g