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steposvetlana [31]
3 years ago
7

If 22.5L of nitrogen at 748 mm Hg are compressed to 725mm Hg at constant temperature. What is the new volume?

Chemistry
1 answer:
Dahasolnce [82]3 years ago
6 0

Answer:

23.2L

Explanation:

The following were obtained from the question:

V1 = 22.5L

P1 = 748 mmHg

P2 = 725mmHg

V2 =?

The new volume can be obtained by doing the following:

P1V1 = P2V2

22.5 x 748 = 725 x V2

Divide both side by 725

V2 = (22.4 x 748) /725

V2 = 23.2L

The new volume is 23.2L

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Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

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