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3 years ago

If 22.5L of nitrogen at 748 mm Hg are compressed to 725mm Hg at constant temperature. What is the new volume?

Chemistry

1 answer:

Dahasolnce [82]3 years ago

6 0

Answer:

23.2L

Explanation:

The following were obtained from the question:

V1 = 22.5L

P1 = 748 mmHg

P2 = 725mmHg

V2 =?

The new volume can be obtained by doing the following:

P1V1 = P2V2

22.5 x 748 = 725 x V2

Divide both side by 725

V2 = (22.4 x 748) /725

V2 = 23.2L

The new volume is 23.2L

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3 years ago

How many moles in 4.93 x 10E23 atoms of silver?

leva [86]

<h3>Answer:</h3>

0.819 mol Ag

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

4.93 × 10²³ atoms Ag

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 4.93 \cdot 10^{23} \ atoms \ Ag(\frac{1 \ mol \ Ag}{6.022 \cdot 10^{23} \ atoms \ Ag})$
Divide: $\displaystyle 0.818665 \ mol \ Ag$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.818665 mol Ag ≈ 0.819 mol Ag

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