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Nana76 [90]
3 years ago
15

NEED HELP ASAP 50 POINTS 20 MINS LEFT

Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:

look at the picture I have sent

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Check the picture below.

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3 years ago
I need answers for the question below to end a debate. Explain why that is the answer too.
IRINA_888 [86]
PEMDAS. Parenthesis comes first. 3+2 = 5 which is then multiplied to 6/2 which is 3 so 3 x 5 is 15. 
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4 years ago
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The lifetime of a battery has the exponential distribution with mean 6.9 months. If it fails, I immediately replace it with anot
irga5000 [103]

Answer:

You should <u>carry 2 other batteries.</u>

Step-by-step explanation:

If the average life of each battery tends to last 6.9 months, and what you need is a year of battery supply, you probably need to carry two batteries.

The battery inside the flashlight has probably already spent much of its half-life.

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5 0
3 years ago
You purchase a car worth $25077 and make a down payment of $3560. You intend to repay the balance of the car with month end car
zubka84 [21]

Answer:

value of buyout is $4185.74

Step-by-step explanation:

given data

car worth = $25077

down payment = $3560

monthly payment = $336 = 336 × 6 = $2016 per semi annually

time = 5 year  = 10 half yearly

rate = 4.04 %

to find out

value of final buyout

solution

we know here loan amount will be 25077 - 3560 = $21517

and we find present value first by formula that is

present value = \frac{amount(1+r)^t - 1}{r (1+r)^t}

put here t = 10 and r = \frac{4.04}{200}

so

present value = \frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}

present value = 18089.96

so

loan unpaid amount is here

loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

so

now we calculate value of buyout

that is express as

amount = principal × (1+r)^{t}

amount = 3427.04 × (1+\frac{4.04}{200})^{10}

amount = 4185.74

so value of buyout is $4185.74

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VikaD [51]

Answer:

c I think

Step-by-step explanation:

can you help me with this question In Lines 23 and 24 of his poem "Chicago", Sandburg uses which poetic device? A Simile - a comparison of two unlike things using "like" or "as" B. Metaphor - a comparison of two unlike objects C. Repetition

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