The solution set to the equation (x+1) =9 is which of the following? 4

Mathematics

1 answer:

likoan [24]3 years ago

8 0

Answer:

Step-by-step explanation: if x+1=9 all you have to do is subtract 9-1 and then you get your answer

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Can someone help me plzz

Rashid [163]

Let's go through each answer choice and eliminate the choices.

a) 6(2/3) = 4, this is less than 6, making it our correct answer, but still go and check each answer
b) 6(2/3) again = 4, this is less than 6, making this answer choice wrong.
c) 6(3/2) = 9, this is greater than 6, making this answer choice wrong.
d) 6(3/3) = 6, this is equal to 6, making this answer choice wrong.

8 0

3 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$