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yanalaym [24]
3 years ago
12

NEED ALGEBRA HELP! Pls help I will do anything :(

Mathematics
1 answer:
Lisa [10]3 years ago
5 0
The answer is x= 3,8
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What is one equation that can only be true if b=2?
arlik [135]

Answer:

1+1 = 2

Step-by-step explanation:

-1 + 3 = 2

6 0
3 years ago
The width of a rectangle is 7 less than the length. If the perimeter of the rectangle is 43.6 inches, what is the area of the re
Lera25 [3.4K]

Call the length a, the width b

Perimeter = (a+b) x 2

And since we have (a+b) x 2 = 43.6, a + b = 43.6 : 2 = 21.8

a + b = 21.8
a - b = 7

-> a + b + (a - b) = 28.8
2a = 28.8
a = 14.4
b = 7.4

So, the area of the rectangle is 14.4 x 7.4 = 106.56

8 0
2 years ago
A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.
qwelly [4]
A = 0.9 o 
<span>so, </span>
<span>o = a/0.9 = 1.111a </span>
<span>so, the orange is 11% heavier than the apple. 

glad i could help(:</span>
6 0
4 years ago
Read 2 more answers
Please help me ASAP!!
vekshin1

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Consider the function on the interval (0, 2π). f(x) = sin x + cos x (a) Find the open intervals on which the function is increas
Annette [7]

Answer:Increasing in x∈(0,π/4)∪(5π/4,2π) decreasing in(π/4,5π/4)

Step-by-step explanation:

given f(x) = sin(x) + cos(x)

f(x) can be rewritten as \sqrt{2} [\frac{sin(x)}{\sqrt{2} }+\frac{cos(x)}{\sqrt{2} }  ]..................(a)\\\\\ \frac{1}{\sqrt{2} } = cos(45) = sin(45)\\\\

Using these result in equation a we get

f(x) = \sqrt{2} [ cos(45)sin(x)+sin(45)cos(x)]\\\\= \sqrt{2} [sin(45+x)]..........(b)

Now we know that for derivative with respect to dependent variable is positive for an increasing function

Differentiating b on both sides with respect to x we get

f '(x) = f '(x)=\sqrt{2}  \frac{dsin(45+x)}{dx}\\ \\f'(x)=\sqrt{2} cos(45+x)\\\\f'(x)>0=>\sqrt{2} cos(45+x)>0

where x∈(0,2π)

we know that cox(x) > 0 for x∈[0,π/2]∪[3π/2,2π]

Thus for cos(π/4+x)>0 we should have

1) π/4 + x < π/2  => x<π/4  => x∈[0,π/4]

2) π/4 + x > 3π/2  => x > 5π/4  => x∈[5π/4,2π]

from conditions 1 and 2 we have  x∈(0,π/4)∪(5π/4,2π)

Thus the function is decreasing in x∈(π/4,5π/4)

5 0
3 years ago
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