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mart [117]
4 years ago
5

Charlie is choosing between two exercise routines.

Mathematics
1 answer:
julia-pushkina [17]4 years ago
3 0
Waking would burn more calories. I think. I may be wrong. Sorry.
You might be interested in
What is the equation of a line that is parallel to 2x+3y=10 and passes through the point (-4,5)
Vikki [24]

Answer:

-4+2x-3

Step-by-step explanation:

7 0
3 years ago
An object is launched from the ground. The object’s height, in feet, can be described by the quadratic function h(t) = 80t – 16t
steposvetlana [31]
Would you like me to help walk you through this with you figuring out the work?
Or would you prefer just an answer in math form with me explaining it along the way?

<span>h(t) = 80t – 16t^2
When you are on the ground we have zero height, h(t) = 0. This is saying that at some amount of time we will call t, the object will hit the ground. Now we solve for t to get that time 
so we sub h(t) for 0.
0=80t-16t^2 move the -16t^2 to the other side
 16t^2=80t   divide both sides by t
16t=80   divide both sides by 16
t=5
Now... it is important to realize that there are going to be 2 answers to this equation as you have a t^2. The other answer is 0. Obviously, unless the object started on the ground, the time to hit the ground is not 0 and that answer is ruled out.



</span>
6 0
3 years ago
Read 2 more answers
HHHHEEEELLLLPPPP!!!!
garri49 [273]

Answer:

28%

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Pls help me with this question and show your work!
Anon25 [30]
It’s the slope formula i’m pretty sure . So it would be 5-5 and then 3-2 . so 0/-1
4 0
3 years ago
The area of the shaded portion of the rectangle is how many units larger than the area of the unshaded portion of the rectangle?
slega [8]

Answer:

(x^{2}-x-2)\ units^{2}

Step-by-step explanation:

step 1

Calculate the area of the shaded portion

A1=(2x+3)(x+1)\\ \\A1=2x^{2}+2x+3x+3\\ \\A1=(2x^{2}+5x+3)\ units^{2}

step 2

Calculate the area of the unshaded portion

A2=(x+5)(x+1)\\ \\A2=x^{2}+x+5x+5\\ \\A2=(x^{2}+6x+5)\ units^{2}

step 3

Find the difference of the areas

A1-A2=(2x^{2}+5x+3)-(x^{2}+6x+5)=(x^{2}-x-2)\ units^{2}

7 0
4 years ago
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