CAN YOU GUYS PLEASE HELP ME? THANK YOU!

Assume that a driver faces the following loss distribution:Outcome Probability12,000 0.15 0 0.851. What is the expected loss?2.

xxMikexx [17]

Answer:

- 1800 ; 4284.8579 ;

Step-by-step explanation:

Given the table :

Outcome _____ probability

-12000 ________ 0.15

__ 0 __________ 0.85

Expected loss, m: Σx*p(x)

(-12000 * 0.15) + (0 * 0.85)

-1800 + 0 = - 1800

Standard deviation = sqrt(Var(x))

Var(x) = Σx²*p(x) - m²

(-12000^2 * 0.15) + (0^2 * 0.85)] - 1800^2

21,600,000 - 3240000

= 18360000

Standard deviation = sqrt(18360000)

Standard deviation = 4284.8579

3 0

2 years ago

Eamon is arranging 39 books on 3 shelves. If he puts the same number of books on each shelf, how many books will there be on eac

blagie [28]

39 times 3 = 117. Hope this helps

7 0

3 years ago

Assume that a computer was used to generate the given confidence interval for the population mean. Find the sample mean or margi

stealth61 [152]

Answer:

The sample mean is

b.3.55

The margin of error is

0.32

Step-by-step explanation:

Deep explanation about a confidence interval

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*215 = 353.675$

The lower end of the interval is the mean subtracted by M. So it is 6.4 - 0.3944 = 6.01 hours.

The upper end of the interval is the mean added to M. So it is 6.4 + 0.3944 = 6.74 hours.

In this problem:

The deep explanation is not that important.

We just have to recognize that the interval has a lower end and an upper end. The distance from both the upper and the lower end to the mean is M. This means that the sample mean is the halfway point between the lower end and the upper end.

The margin of error is the distance of these two points(lower and upper end) to the mean.

In our interval

Lower end: 3.23

Upper end: 3.87

Sample mean

$M = \frac{3.23 + 3.87}{2} = 3.55$

So the correct answer is:

b.3.55

The margin of error is

3.87 - 3.55 = 3.55 - 3.23 = 0.32

4 0

3 years ago

Can someone help I will give the brainliest Plz help u will get 50 points

lara [203]

Answer:

B.) 6

2.) 70

3.) 56

Step-by-step explanation:

B.) 2(6) - 6

= 12 - 6

=6

2.) 7(2(3)+4)

=7(6+4)

=42+28

=70

3.) 10(3) + 4(3) + 14

= 30 + 12 + 14

= 42+14

=56

Have a wonderful day

:)

7 0

3 years ago

The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili

Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

$\lambda= 4.5$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

a) No accidents occur in one week.

$P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111$

b) 5 or more accidents occur in a week.

$P( x \geq 5) = 1-\displaystyle \sum P(x$

c) One accident occurs today.

The mean number of accidents per day is given by

$\lambda = \dfrac{4.5}{7} = 0.64$

$P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747$

5 0

3 years ago