Answer:
yniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh olleh
Step-by-step explanation:yniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era csacasccacwoh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh olleh
Convert to equivalent fractions to see
Both bottom s can be 6
So times the half by 3
And times the third by 2
1/2=3/6
1/3=2/6
So she has a total of 5/6 of the movie accounted for...
So the left over is 1/6
1/6 at nighttime
Answer:
x = - 2, x = - 
Step-by-step explanation:
Given
5x² + 1 = - 13x - 5 ( add 13x - 5 to both sides )
5x² + 13x + 6 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 5 × 6 = 30 and sum = 13
The factors are 10 and 3
Use these factors to split the x- term
5x² + 10x + 3x + 6 = 0 ( factor the first/second and third/fourth terms )
5x(x + 2) + 3(x + 2) = 0 ← factor out (x + 2) from each term
(x + 2)(5x + 3) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
5x + 3 = 0 ⇒ 5x = - 3 ⇒ x = -
Answer:
The inequality 14
Cecil had 14 boxes of lightbulbs when he started
I think not 100% sure
Step-by-step explanation:
Hope this helps :)
Answer:
Linear pairs are congruent
That's the answer
