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Marizza181 [45]
3 years ago
11

PLEASE HELP ME A.S.A.P! btw the activity is in Arabic.

Mathematics
1 answer:
irina1246 [14]3 years ago
7 0

Answer:

plz convert it i can't understand

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What is 15% of 287? Calculate the percentages. Make sure to show all your work!
jolli1 [7]

Answer:

Step-by-step explanation:15 percent *287 = (15/100)*287 = (15*287)/100 = 4305/100 = 43.05Now we have: 15 percent of 287 = 43.05Question: What is 15 percent of 287?We need to determine 15% of 287 now and the procedure explaining it as suchStep 1: In the given case Output Value is 287.Step 2: Let us consider the unknown value as x.Step 3: Consider the output value of 287 = 100%.Step 4: In the Same way, x = 15%.Step 5: On dividing the pair of simple equations we got the equation as under287 = 100% (1).x = 15% (2).(287%)/(x%) = 100/15Step 6: Reciprocal of both the sides results in the following equationx%/287% = 15/100Step 7: Simplifying the above obtained equation further will tell what is 15% of 287x = 43.05%Therefore, 15% of 287 is 43.05

6 0
2 years ago
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Which of the following relations is a function?
Agata [3.3K]

Answer:

D

Step-by-step explanation:

Because in D, there no x-value that are repeating in the list.

For example A, the value 8 and -8 are being repeated twice, which makes this relation not a fuction.

5 0
3 years ago
What is 1/8(5x+4)=3/4
barxatty [35]

Answer:

Step-by-step explanation:

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4 years ago
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What is the slope of the line? y = 3x + 9
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The answer is 3..y=mx+b where m is the slope
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Find all relative extrema of the function. Use the Second Derivative Test where applicable. (If an answer does not exist, enter
Lapatulllka [165]

Answer:

Relative minimum: \left(-\frac{5}{2}, -\frac{33}{4}\right), Relative maximum: DNE

Step-by-step explanation:

First, we obtain the First and Second Derivatives of the polynomic function:

First Derivative

f'(x) = 2\cdot x + 5 (1)

Second Derivative

f''(x) = 2 (2)

Now, we proceed with the First Derivative Test on (1):

2\cdot x + 5 = 0

x = -\frac{5}{2}

The critical point is -\frac{5}{2}.

As the second derivative is a constant function, we know that critical point leads to a minimum by Second Derivative Test, since f\left(-\frac{5}{2}\right) > 0.

Lastly, we find the remaining component associated with the critical point by direct evaluation of the function:

f\left(-\frac{5}{2} \right) = \left(-\frac{5}{2} \right)^{2} + 5\cdot \left(-\frac{5}{2} \right) - 2

f\left(-\frac{5}{2} \right) = -\frac{33}{4}

There are relative maxima.

6 0
3 years ago
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