Answer:
This quadrilateral is a SQUARE.
When we plot these points, we realize that they are equal distance apart.
So, when a quadrilateral has sides that are equal distance apart, that quadrilateral is a square.
Let me know if this helps!
<h3>The solution as an ordered pair is (x,y) = (2,2)</h3><h3>x = 2 and y = 2 pair up together.</h3>
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Work Shown:
4x+2y = 12
4x+2( y ) = 12
4x+2( 2x-2 ) = 12 ... replace y with 2x-2
4x+2( 2x ) + 2( -2 ) = 12 ... distribution rule
4x+4x-4 = 12
8x-4 = 12
8x-4+4 = 12+4 ... add 4 to both sides
8x = 16
8x/8 = 16/8 ... divide both sides by 8
x = 2 is the first part of the answer
Use x = 2 to find y
y = 2x-2
y = 2(2)-2 ... replace x with 2
y = 4-2
y = 2 is the second part of the answer
Answer:
The answer to your question is:th first option is correct.
Step-by-step explanation:
Here we have and hyperbola with center (0, 1), and the hyperbola is horizontal because x² is positive.
Equation
y - k = ±
Process
Find a, b
a² = 9
a = 3
b² = 5
b = √5
h = 0 and k = 1
Substitution
y - 1 = ±
Equation 1
y = 
Equation 2
y = -
Answer:
Domain : all real numbers
Range: All numbers greater than 2
Step-by-step explanation:
The shark. (Haha, I'm sorry.)
There are no restrictions on the x. X can be any real number.
The range, however, does have restrictions. The range has to be a number greater than 0.
Why?
Because any number that you put in for x won't make the range less than 2. If you put in zero for x, the range is 2.
Answer:
The ray that goes parallel to the main axis after passing through the lens should also be parallel from the object to the lens
Step-by-step explanation:
To form the image of an object using a convex lens, ray diagrams are used. The following steps are followed when drawing ray diagrams.
1) Light rays are drawn from the object incidented on the lens and parallel to the principal axis. The incident light refracts (bends) through the lens and converges at the focal point at the other side of the lens.
2) Another incident light passes through the optical centre undeflected and intersect with the refracted ray at the other side of the lens.
Based on the above points, Roshan made an error by drawing the ray that goes parallel to the main axis and after passing through the lens made the same ray to be parallel from the object to the lens instead of refracting (bending) after passing through the lens.
