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3 years ago

Pleaseeee need helpl

Mathematics

1 answer:

Nesterboy [21]3 years ago

5 0

I think that it is the 3rd one

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Please help asap, brainliest,thanks, and 50 points. Thank you soooo much! <3

Anuta_ua [19.1K]

Answers:

1) $x^{8} y^{8}$

2) $y^{3} \sqrt{y}$

3) $5x^{4} \sqrt{6}$

4) $\sqrt{7}$

5) $\frac{\sqrt{z}}{z}$

Step-by-step explanation:

1) $\sqrt{x^{16} y^{36}}$

Rewriting the expression:

$(x^{16} y^{36})^{\frac{1}{2}}$

Multiplying the exponents:

$x^{\frac{16}{2}} y^{\frac{36}{2}}$

Simplifying:

$x^{8} y^{8}$

2) $\sqrt{y^{7}}$

Rewriting the expression:

$\sqrt{y^{6} y}=(y^{6} y)^{\frac{1}{2}}$

Multiplying the exponents:

$y^{\frac{6}{2}} y^{\frac{1}{2}}$

Simplifying:

$y^{3} y^{\frac{1}{2}}=y^{3} \sqrt{y}$

3) $\sqrt{150 x^{8}}$

Rewriting the expression:

$\sqrt{(6)(25) x^{8}}$

Since $\sqrt{25}=5$ :

$5x^{4}\sqrt{6}$

4) $\frac{7}{\sqrt{7}}$

Multiplying numerator and denominator by $\sqrt{7}$ :

$\frac{7}{\sqrt{7}} (\frac{\sqrt{7}}{\sqrt{7}})=\frac{7}{7\sqrt{7}}$

Simplifying:

$\sqrt{7}$

5) $\frac{5z}{\sqrt{25 z^{3}}}$

Rewriting the expression:

$\frac{5z}{5z \sqrt{z}}$

Simplifying:

$\frac{1}{\sqrt{z}}$

Since we do not want the square root in the denominator, we can multiply numerator and denominator by $\sqrt{z}$ :

$\frac{1}{\sqrt{z}}(\frac{\sqrt{z}}{\sqrt{z}})$

Finally:

$\frac{\sqrt{z}}{z}$

3 0

4 years ago

06.07 equivalent expressions module six project 1 part2

Firlakuza [10]

HEYYYYYY HIIIIII HEYYYY

7 0

3 years ago

Read 2 more answers

Mrs. Smith is having a birthday party for her grandson. 75 people will be there. If 3/5 of them are bringing desserts and 1/5 ar

Mandarinka [93]

Answer:

The answer is 15 people.

Step-by-step explanation:

If one fifth is bringing candy and three fifths is bringing dessert than that already four fifths of the people who aren't bringing punch so one fifth of the people are bringing punch so one fifth of 75 is equal to 15

8 0

3 years ago

Im really confused Lol can someone help?

Lemur [1.5K]

Answer:

your do it on your own

Step-by-step explanation:

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.

y=-16x^2+129x+119

y=−16x

+129x+119

7 0

3 years ago

Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?

noname [10]

B. The answer is b because -2m and -5m together equal -7m-8, and on the other side of the equal sign 3+-7+m equal -4+m

4 0

4 years ago