Question

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Answer 1

Answers:

1) $x^{8} y^{8}$

2) $y^{3} \sqrt{y}$

3) $5x^{4} \sqrt{6}$

4) $\sqrt{7}$

5) $\frac{\sqrt{z}}{z}$

Step-by-step explanation:

1) $\sqrt{x^{16} y^{36}}$

Rewriting the expression:

$(x^{16} y^{36})^{\frac{1}{2}}$

Multiplying the exponents:

$x^{\frac{16}{2}} y^{\frac{36}{2}}$

Simplifying:

$x^{8} y^{8}$

2) $\sqrt{y^{7}}$

Rewriting the expression:

$\sqrt{y^{6} y}=(y^{6} y)^{\frac{1}{2}}$

Multiplying the exponents:

$y^{\frac{6}{2}} y^{\frac{1}{2}}$

Simplifying:

$y^{3} y^{\frac{1}{2}}=y^{3} \sqrt{y}$

3) $\sqrt{150 x^{8}}$

Rewriting the expression:

$\sqrt{(6)(25) x^{8}}$

Since $\sqrt{25}=5$:

$5x^{4}\sqrt{6}$

4) $\frac{7}{\sqrt{7}}$

Multiplying numerator and denominator by $\sqrt{7}$:

$\frac{7}{\sqrt{7}} (\frac{\sqrt{7}}{\sqrt{7}})=\frac{7}{7\sqrt{7}}$

Simplifying:

$\sqrt{7}$

5) $\frac{5z}{\sqrt{25 z^{3}}}$

Rewriting the expression:

$\frac{5z}{5z \sqrt{z}}$

Simplifying:

$\frac{1}{\sqrt{z}}$

Since we do not want the square root in the denominator, we can multiply numerator and denominator by $\sqrt{z}$:

$\frac{1}{\sqrt{z}}(\frac{\sqrt{z}}{\sqrt{z}})$

Finally:

$\frac{\sqrt{z}}{z}$