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chubhunter [2.5K]
3 years ago
6

6 2/3 divided by 1 1/2 =

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0

Answer:

1 7/33

Step-by-step explanation:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

203÷112

Applying the fractions formula for division,

=20×23×11

=4033

Simplifying 40/33, the answer is

=1733

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The blue dot is at what value on the number line?
Ksenya-84 [330]

Answer:

17.

Step-by-step explanation:

one dash is equal to 2. so just go by twos

4 0
2 years ago
Could someone help me with these problems, please :)​
Elanso [62]

Answer:

A for first one and C

Step-by-step explanation:

4 0
2 years ago
Suppose you budgeted $2800 for fuel expenses for the year. How many miles could you drive if gas were $2.70 per gallon and your
Julli [10]

Answer:

29037.036 miles

Step-by-step explanation

There are two possible ways to solve this problem.

The first option starts with the $2800 dollars for the years. You first want to divide this by $2.70, because it will give you the amount of gallons of gas you can buy with that money.

2800/2.70 = 1037.037

This means you can buy 1037.037 gallons of gas in the year. Now you need to convert this to miles by multiplying by the amount of miles per gallon.

1037.037 x 28 = 29037.036 gallons

The second way to look at this is dimensional analysis. If you have learned this, then continue on reading this, but if you haven't I might only confuse you. I only suggest this because it can make it a little easier.

For the dimensional analysis, you need to start with what you are given and move to what you need to know, so you will start with the $2800 dollars and move to gallons. $2.70 per gallon and 28 miles per gallon are your conversion factors.

Set it up like this:

2800 dollars  * \frac{1 gallon}{2.70 dollars} * \frac{28 miles}{1 gallon}  = 29037.036 miles

This allows the equation to be more organized, and you can check your work by canceling the units.

Hope this helps.

3 0
2 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

4 0
3 years ago
HELP
Shtirlitz [24]

x(x + 9-x) = 6^2

9x = 36

x = 4


Answer

c. 4

4 0
3 years ago
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