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3 years ago

10

In 1918, the temperature in Alaska dropped from 52 degrees to -23 degrees in 15 hours. What was the average hourly change in tem

perature?

1 answer:

marissa [1.9K]3 years ago

7 0

To do this we need to see how many degrees it dropped then divide by time (15 hr.).

52 - (-23)
75

75/15
5 deg/hr

Hope this helped!

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A sphere and cylinder have the same radius and height. The volume of the cylinder is 30m^3. What is the volume of the sphere?

Aleonysh [2.5K]

Answer:

15 is the volume I hope I helped

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3 years ago

What letter stays the same when reflected over the x-axis

valina [46]

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3 years ago

If 2x − 4(x + 1) = −12, evaluate x2 − 1.

Vlad [161]

2x-4(x+1)=-13
1) we solve this equation:
2x-4(x+1)=-12
2x-4x-4=-12
-2x=-12+4
-2x=-8
x=-8/-2
x=4

2) we evalute x²-1
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Answer: 15

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3 years ago

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

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3 years ago

I need help i am timed

Vadim26 [7]

Answer:

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Step-by-step explanation: im not sure on the last two but i tried?

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3 years ago