Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
Hello There!
2y x 2y = 4y²
2y x 8 = 16y.
Put it together and you get the answer of:
4y² + 16y.
Hope This Helps You!
Good Luck :)
- Hannah ❤
No one wants to date you or anyone else because this is a Q&A app for homework, Quizs, and Classwork.
The next step would be 10n=5x-7+9-x
sincerely- brock<span />