Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
To estimate, round 3102 to 3100
round 1-10 to 2500
1-70 to 2100
1-80 to 2900
2900+2100+2500+3100=10600mi
Yes it is reasonable because you add and subtract numbers when estimating, however it is not exact
Step-by-step explanation: Standard form is when we take a polynomial and we write it in order from the greatest degree to the smallest degree.
Let's look at an example which I provided in the image attached.
In this polynomial, I have 2 degrees, 1 degree, and 1 degree above the <em>x</em>.
This is not in the form of least to greatest so I need to write it in descending order. Our constant which in this is 27 will be last in polynomial.
So, you look at the degree of each term and then write each in term in order of degree from greatest to least (descending order).
Answer:
none of the tables shown
Step-by-step explanation:
Inverse variation is
xy = k where k is the constant
xy = 4
in the top table
-2*2 = -4 so it cannot be the first table
In the middle table
-2 * -8 = 16 so it is not the middle table
In the bottom table
-2 *4 = -8 so it is not the bottom table
There must be a table not shown
