Answer:
4 m/s
Step-by-step explanation:
A bird is flying to the right when a gust of wind causes the bird to accelerate leftward at 0.5 m/s^2 for 3 s. After the wind stops, the bird is flying to the right with a velocity of 2.5 m/s.
Assuming the acceleration from the wind is constant, what was the initial velocity of the bird before the gust of wind?
Let say Initial Velocity of Bird = U m/s
Final Velocity of Bird V = 2.5 m/s
acceleration a = -0.5 m/s² ( as opposite to the fly direction)
Time T= 3 sec
Applying formula
V = U + aT
=> 2.5 = U + (-0.5)3
=> 2.5 = U -1.5
=> U = 4 m/s
the initial velocity of the bird before the gust of wind = 4 m/s
304020 just say it in your head it will make sence
Complete question :
Answer:
(-5) * (20) * (3)
Step-by-step explanation:
Diving 5 feets deeper = descent = negative 5 Feets
Each time instrument is checked = (60/3) = depth of 20 feets
Number of times instrument is checked = 3
Hence, maximum depth :
Diving 5 feets deeper * Each time instrument is checked = depth of 20 feets * Number of times instrument is checked
(-5) * (20) * (3) = - 60
24a+48=18a-36
24a-18a=-36-48
6a=-74
a=-74/6
a=-37/3
