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kkurt [141]
3 years ago
14

Given the diagram, a student wrote:

Mathematics
1 answer:
melomori [17]3 years ago
6 0

What's wrong:

<W is congruent to <G not <F, and <V is congruent to <F not <G.

Statement:

<W is congruent to <G, and <V is congruent to <F because alternate interior angles are congruent. Therefore, Triangle WEV ~ Triangle FEG, by AA.

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Which relation is also a function?​
Elan Coil [88]
If I remember correctly it should be B because every input has to have 1 output. I apologize if it’s wrong ( I haven’t had those problems since 8th grade I’m currently in 10th)
4 0
3 years ago
24 pencils costing a total of $3.00 how many cents per a pencil
hram777 [196]

Answer:

$0.125 , so 12.5 cents per pencil

Step-by-step explanation:

\frac{3.00}{24}

You can double check this by doing 0.125*24 , making sure it equals 3.

3 0
3 years ago
Read 2 more answers
Okay i need help finding y x 6 for y = 2/3 please help
aleksandr82 [10.1K]
First, you need to substitute y for 2/3:

2/3 • 6

Next, change 6 into a fraction and multiply straight across:

2/3 • 6/1
12/3

Finally, simplify it to its simplest form:

4
Your answer should be 4.
Hopefully that helped!
4 0
3 years ago
PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!
jonny [76]

Answer:

Here we will use the relationships:

a^n*a^m = a^{n + m}

(a^n)^m = a^{n*m}

\frac{a^n}{a^m} = a^{n - m}

And a number:

a^n

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) 5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}

This is between zero and 1,

B) \frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}

This is greater than 1, because the exponent is positive.

C) (\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) \frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0
3 years ago
Please help me i need it :)
Musya8 [376]

Answer:

I think the incenter of LO is 27 like ML

Step-by-step explanation:

because LO is almost the same of ML

5 0
3 years ago
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