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3 years ago

Please help me with this, thanks

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

5 0

The answer is 0.40 or 0.4

DedPeter [7]3 years ago

4 0

The answer is 0.4 hope this helps

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What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?

mars1129 [50]

The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2

the sum of a geometric seequence is
$S_{n}=\frac{a_{1}(1-r^{n})}{1-r}$
a1=1
r=2
we want to find $S_{10}$ (since we minus 1, the highest exponet is 9 so add 1 to make it correct)

$S_{10}=\frac{1(1-2^{10})}{1-2}$
$S_{10}=\frac{(1-1024}{-1}$
$S_{10}=\frac{(-1023}{-1}$
$S_{10}=1023$

3 0

3 years ago

Read 2 more answers

Solve. 90<img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-formula"> = 27.

Irina-Kira [14]

Answer: $x$ ≈ $0.732$

Step-by-step explanation:

You need to find the value of the variable "x".

To solve for "x" you need to apply the following property of logarithms:

$log(m)^n=nlog(m)$

Apply logarithm on both sides of the equation:

$90^x=27\\\\log(90)^x=log(27)$

Now, applying the property mentioned before, you can rewrite the equation in this form:

$xlog(90)=log(27)$

Finally, you can apply the Division property of equality, which states that:

$If\ a=b,\ then\ \frac{a}{c}=\frac{b}{c}$

Therefore, you need to divide both sides of the equation by $log(90)$ . Finally, you get:

$\frac{xlog(90)}{log(90)}=\frac{log(27)}{log(90)}\\\\x=\frac{log(27)}{log(90)}$

$x$ ≈ $0.732$

7 0

3 years ago

Jack crawled 3 ft and Christine crawled 3⁄4 the distance Jack crawled. If you add the distance they each crawled together, what

LUCKY_DIMON [66]

Christine crawled:
3 ft* (3/4)= 2.25 ft.

3 ft+ 2.25 ft= 5.25 ft

We already know that 1 ft= 12 in.

5.25 ft* (12in/ 1 ft)= 63 in.

The total distance the two children crawled together is 63 in~

5 0

3 years ago

Which function will have a y-intercept at –1 and an amplitude of 2?

Angelina_Jolie [31]

Answer:

Options B and D.

Step-by-step explanation:

The general form of sine function

$h(x)=A\sin (Bx+C)+D$

where, |A| is amplitude, $\frac{2\pi}{B}$ is period, $\frac{-C}{B}$ is phase shift and D is y-intercept.

The general form of cosine function

$h(x)=A\cos (Bx+C)+D$

where, |A| is amplitude, $\frac{2\pi}{B}$ is period, $\frac{-C}{B}$ is phase shift and D is y-intercept.

In function, $f(x)=-\sin x-1$

Amplitude : $|A|=1$

y-intercept : -1

In function, $f(x)=-2\sin x-1$

Amplitude : $|A|=2$

y-intercept : -1

In function, $f(x)=-\cos x$

Amplitude : $|A|=1$

y-intercept : 0

In function, $f(x)=-2\cos x-1$

Amplitude : $|A|=2$

y-intercept : -1

Therefore, the correct options are B and D.

4 0

3 years ago

Read 2 more answers

What is the sum of the first 10 terms of the sequence 2, 6, 18,54...?

leonid [27]

Answer:

This is a sequence where you multiply that number 3 times. For example, 2 x 3 = 6. 6 x 3 = 18. 18 x 3 = 54 and so on. Therefore, multiplying 3 by the number is the Answer.

4 0

3 years ago