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likoan [24]
3 years ago
13

Can someone help me with this?? thanks

Mathematics
2 answers:
viva [34]3 years ago
7 0
Number of tickets: T.
Number of customers: c 
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150

For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)

Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150

Kaylis [27]3 years ago
5 0
150 tickets is y-intercept, b
3 tickets/customer is slope, m
selling is negative slope
y = mx + b

y = -3c + 150
graph for this is top right.
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Suppose a bag contains many marbles, 54% of which are purple. You draw 5 marbles from the bag with replacement.
dolphi86 [110]

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P(x) = \frac{n!}{x!(n-x)!}*p^x*(1-p)^{n-x}\\\\P(2) = \frac{5!}{2!(5-2)!}*0.54^2*(1-0.54)^{5-2}\\\\P(2) = 10*0.54^2*0.46^3\\\\P(2) = 0.283831776\\\\

The \frac{n!}{x!(n-x)!} portion is from the nCr combination formula. The exclamation marks indicate a factorial.

Alternatively, you could use Pascal's Triangle for that portion.

<h3>Answer: 0.283831776</h3>

This decimal value is exact. Round it however you need to.

============================================================

Part B

To find the expected value, aka the mean, we multiply the sample size and probability of getting a purple marble on any single selection.

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