For what value(s) of k will the relation not be a function?

Mathematics

1 answer:

kolbaska11 [484]3 years ago

8 0

Answer:

See below

Step-by-step explanation:

The relation is not a function when x -value is same but y- values are different.

k^2 = 4k
k = 0, k = 4

k^2 - 5k = k + 7
k^2 - 6k = 7
k^2 - 6k + 9 = 16
k - 3 = 4 ⇒ k = 7
k - 3 = -4 ⇒ k = -1

k^3 - 5k^2 + 3k = -k
k^3 - 5k^2 + 4k = 0
k(k^2 - 5k + 4) = 0
k = 0, k = 1, k = 4

|k + 1| + 2 = 8
|k + 1| = 6
k = 5, k = -7

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