For what value(s) of k will the relation not be a function?
1 answer:
Answer:
Step-by-step explanation:
The relation is not a function when x -value is same but y- values are different.
#1
#2
- k^2 - 5k = k + 7
- k^2 - 6k = 7
- k^2 - 6k + 9 = 16
- k - 3 = 4 ⇒ k = 7
- k - 3 = -4 ⇒ k = -1
#3
- k^3 - 5k^2 + 3k = -k
- k^3 - 5k^2 + 4k = 0
- k(k^2 - 5k + 4) = 0
- k = 0, k = 1, k = 4
#4
- |k + 1| + 2 = 8
- |k + 1| = 6
- k = 5, k = -7
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